Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest substring is "b", with the length of 1. 这个应该是一个典型的动态规...
详见:https://leetcode.com/problems/longest-substring-without-repeating-characters/solution/
classSolution{public:intlengthOfLongestSubstring(string s){if(s.length()==0){return0;}unordered_map<char,int>hash;intbegin=0,end=0;intrepeat=0;intmax_length=0;while(end0){repeat++;}hash[s[end]]++;end++;while(repeat>0){if(hash[s[begin]]>1){repeat--;}hash[s[begin]]--;begin++...
Longest Substring no Repeat Characters 今天的题目是第3题,medium难度. LongestSubstring Without Repeating Characters Given a string, find the length of the longest substring without repeating characters. Example 1: Input:"abcabcbb"Output:3Explanation:The answeris"abc",withthe lengthof3. Example 2: I...
Given a string, find the length of the longest substring without repeating characters. Examples: Given"abcabcbb",the answeris"abc",which the lengthis3.Given"bbbbb",the answeris"b",withthe length of1.Given"pwwkew",the answeris"wke",withthe length of3.Note that the answer must be a sub...
Note that the answer must be a substring, "pwke" is a subsequence and not a substring. 1. 2. 3. 4. 分析 题目的意思是:找出字符串中的最长非重复子串。 map存储的是该字符串的坐标,初始为-1。 遍历字符串,如果前面有重复的,就把前面离现在这个字符最近的字符的索引记录在repeatIndex中,如果没有重...
The longest substring method is very helpful if we want to get the longest substring that does not repeat the same alphabets. In this method, we will use a loop that goes through the complete string, checks each element one by one, and gives the non-repeated substring of the original ...
Leetcode 3 Longest Substring Without Repeating Characters Given a string, find the length of thelongest substringwithout repeating characters. 方法1:利用哈希表 时间复杂度为O(n^2),空间复杂度为O(n). 方法2:对于一个字符串,例如qpxrjxkltzyx,我们从头开始遍历时,如果遇到一个之前出现过的字符的话,例如...
We keep moving the left side and deleting the value str[left side] in the map till the current str[right side] is no more than 1. Then, right side continues moving. Repeat this logic to the end.
Given a string, find the length of the longest substring without repeating characters. Example 1: Input:"abcabcbb"Output:3Explanation:The answeris"abc",withthe lengthof3. Example 2: Input:"bbbbb"Output:1Explanation:The answeris"b",withthe lengthof1. ...