Below image shows the output of the above longest palindrome java program. We can improve the above code by moving the palindrome and longest lengths check into a different function. However, I have left that part for you. :) Please let me know if there are any other better implementations ...
String currLongest = s.substring(left + 1, right); // 判断是否比全局最长还长 if(currLongest.length() > longest.length()){ longest = currLongest; } } } 2018/2 class Solution: def longestPalindrome(self, s): """ :type s: str :rtype: str """ maxStr = '' for index in range(...
longestpalindrome=tmp; maxlen=tmp.length(); } } returnlongestpalindrome; } publicstaticString getPalindrome(String s,intbegin,intend) { while(begin>=0&&end
Java我们提供两种方法,由运行时间,我们可以看出使用char[]性能比substring()和charAt()更优。 ** Solution One -- Method One ** ** 6ms, 40.8MB ** class Solution { public String longestPalindrome(String s) { if (s.length() < 1) return s; int curLen = 0; String res = ""; char...
public String longestPalindrome(String s) { if (s == null || s.length() < 2) return s; //return as result String longest = s.substring(0, 1); for (int i = 0; i < s.length()-1; i++) { //get 'ABA' type palindrome ...
先提供第二种方式的解答，通过提交public class Solution {public String longestPalindrome(String s) { int max = Integer.MIN_VALUE;//最长回文子串长度; String result = ""; for(int i=0;i<s.length();i++){ //奇数中心展开 String temp1 = expandFromCenterToEdge(s, i, i);...
class Solution { public: string longestPalindrome(string s) { string manaStr = "$#"; for (int i=0;i<s.size();i++) //首先构造出新的字符串 { manaStr += s[i]; manaStr += '#'; } vector<int> rd(manaStr.size(), 0);//用一个辅助数组来记录最大的回文串长度,注意这里记录的是...
参考:LeetCode:Longest Palindromic Substring 最长回文子串 - tenos中的方法4 动态规划 AC代码: 代码语言:javascript 代码运行次数:0 classSolution{public:stringlongestPalindrome(string s){constint len=s.size();if(len<=1)returns;bool dp[len][len];//dp[i][j]表示s[i..j]是否是回文memset(dp,0,...
Can you solve this real interview question? Longest Palindromic Substring - Given a string s, return the longest palindromic substring in s. Example 1: Input: s = "babad" Output: "bab" Explanation: "aba" is also a valid answer. Example 2: Input
We are checking for palindrome around each character as the palindrome substring can be at any position in the String and continue the while loop until we find any unequal character. Share Prev Post Java program to find duplicate character from a string ...