424. Longest Repeating Character Replacement 仅供自己学习 题目: Given a string s that consists of only uppercase English letters, you can perform at most k operations on that string. In one operation, you can choose an
Given a string that consists of only uppercase English letters, you can replace any letter in the string with another letter at mostktimes. Find the length of a longest substring containing all repeating letters you can get after performing the above operations. Note: Both the string's length ...
每次计算重复字母长度时,当出现更长的可能时,都更新最终的结果。 code 代码语言:javascript 代码运行次数:0 funccharacterReplacement(s string,k int)int{iflen(s)==0{return0}str:=[]byte(s)start,end:=0,0ret:=0c:=make([]int,26)c[str[0]-'A']++forlen(str)>end{maxc:=0fori:=0;i<26;i...
424. Longest Repeating Character Replacement 信息门下皮卡丘 佛系皮卡丘 来自专栏 · Leetcode题解 Given a string s that consists of only uppercase English letters, you can perform at most k operations on that string. In one operation, you can choose any character of the string and change it to...
【nc】 Sliding Window 3/4 longest-repeating-character-replacemen 替换后的最长重复子串,思路:滑动窗口1.设置map存储每个字符的出现次数2.设置l为0,r为0r从0开始向右遍历,计算某一个字符的map[r]maxCharCount=Math.max(maxCharCount,map[r])如果(r-l+1)-maxCharCount
395. Longest Substring with At Least K Repeating Characters,题目Givenastring s andaninteger k,return thelengthofthelongestsubstringof s suchthatthefrequencyofeachcharacterinthissubstringisgreaterthanorequal
424. 替换后的最长重复字符 Longest Repeating Character Replacement 【LeetCode 力扣官方题解】 3246 1 22:04 App 399. 除法求值 Evaluate Division 【LeetCode 力扣官方题解】 5308 -- 10:09 App 567. 字符串的排列 Permutation in String 【LeetCode 力扣官方题解】 5060 2 11:36 App 560. 和为 K 的...
Character stringTemps linéaireCompression donnéeRègle productionGrammaireGiven a text, grammar-based compression is to construct a grammar that generates the text. There are many kinds of text compression techniques of this type. Each compression scheme is categorized as being either off-line or on...
Replace the one 'A' in the middle with 'B' and form "AABBBBA". The substring "BBBB" has the longest repeating letters, which is 4. 大意: 给出一个只由大写字母组成的字符串,你最多可以替换其中的字母k次。寻找执行替换操作后最长的相同字母的长度。
Given a string, find the length of the longest substring without repeating characters. 主要思路: 除了brute force之外,可以使用sliding window的思路来解决,即在碰到与前面的substring相同的character的时候将substring向右滑动再重新寻找。 代码: deflengthOfLongestSubstring(self,s):""" ...