判断是否为回文:再次嵌套一个循环、O(n^3)。 3.java代码详解: public static String longestPalindrome(String s) { if(s.length() <= 1) return s;for(int i = s.length();i > 0; i–){//子串长度for (int j = 0; j <= s.length() – i; j++){ String sub = s.substring(j , i ...
public class LongestPalindromicSubString1 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub System.out.println(longestPalindrome1("babcbabcbaccba")); } public static String longestPalindrome1(String s) { int maxPalinLength = 0; String long...
public class LongestPalindromicSubString1 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub System.out.println(longestPalindrome1("babcbabcbaccba")); } public static String longestPalindrome1(String s) { int maxPalinLength = 0; String long...
public String longestPalindrome(String s) { int maxLength = 0; int maxStart = 0; int len = s.length(); //i是字符串长度 for(int i = 0; i < len; i++){ //j是字符串起始位置 for(int j = 0; j < len - i; j++){ //挨个判断是否回文 if(isPalindrome(s,i,j) && (i+1)>...
public String longestPalindrome(String s) { if (s == null || s.length() < 2) return s; //return as result String longest = s.substring(0, 1); for (int i = 0; i < s.length()-1; i++) { //get 'ABA' type palindrome ...
class Solution { public: string longestPalindrome(string s) { string manaStr = "$#"; for (int i=0;i<s.size();i++) //首先构造出新的字符串 { manaStr += s[i]; manaStr += '#'; } vector<int> rd(manaStr.size(), 0);//用一个辅助数组来记录最大的回文串长度,注意这里记录的是...
Below image shows the output of the above longest palindrome java program. We can improve the above code by moving the palindrome and longest lengths check into a different function. However, I have left that part for you. :) Please let me know if there are any other better implementations...
publicStringlongestPalindrome7(Strings){intn=s.length();Stringres="";boolean[]P=newboolean[n];for(inti=n-1;i>=0;i--){for(intj=n-1;j>=i;j--){P[j]=s.charAt(i)==s.charAt(j)&&(j-i<3||P[j-1]);if(P[j]&&j-i+1>res.length()){res=s.substring(i,j+1);}}}returnres...
public static String longestPalindrome(String s) { if (s.length() < 2) return s; for (int i = 0; i < s.length() - 1; i++) { PalindromeHelper(s, i, i); PalindromeHelper(s, i, i + 1); } return s.substring(index, index + len); ...
We are checking for palindrome around each character as the palindrome substring can be at any position in the String and continue the while loop until we find any unequal character. Share Prev Post Java program to find duplicate character from a string ...