Longest Palindromic Substring 最长回文子串 学习笔记 1. Brute method 第一种方法:直接循环求解, o(n2) o(n^2) 代码语言:javascript 代码运行次数:0 运行 AI代码解释 class Solution: def longestPalindrome(self, s): """ :type s: str :rtype: str "
class Solution: def longestPalindrome(self, s: str) -> str: #def longestPalindrome(s: str) -> str: n = len(s) if n < 2: return s # 如果字符串长度小于2,它本身就是最长的回文子串 # dp[i][j]表示s[i:j+1]是否是回文串 dp = [[False] * n for _ in range(n)] start, max_...
Given a string s, find the longest palindromic substring in s. You may assume that the maximum length of s is 1000. Example: Input: "babad" Output: "bab" Note: "aba" is also a valid answer. Example: Input: "cbbd" Output: "bb" Pyhton代码如下: classSolution(object):deflongestPalindr...
2. sol 1 longest common substring问题 3. dp每增加一个字母,最长列长度只可能增加1or2(思路:以当前字母为尾的最长列): class Solution: def longestPalindrome(self, s: str) -> str: if not s: return '' l = 1 start = 0 for i in range(2, len(s)+1): if i>l+1: if s[i-l-2:i...
题意:Given a stringS, find the longest palindromic substring inS. You may assume that the maximum length ofSis 1000, and there exists one unique longest palindromic substring. 解题思路:最长回文子串求解。 代码: classSolution:#@return a stringdefgetlongestpalindrome(self, s, l, r):whilel >= ...
class Solution { public: string longestPalindrome(string s) { string manaStr = "$#"; for (int i=0;i<s.size();i++) //首先构造出新的字符串 { manaStr += s[i]; manaStr += '#'; } vector<int> rd(manaStr.size(), 0);//用一个辅助数组来记录最大的回文串长度,注意这里记录的是...
leetcode5:Longest Palindromic Substring最长回文子串 python版: class Solution: def longestPalindrome(self, s): """ :type s: str :rtype: str """ start = end = 0 for i in range(len(s)): len1 = self.find(s,i,i) #aba len2 = self.find(s,i,i+1) #abba maxlen = max(len1,...
def longestPalindrome(self, s: str) -> str: # if s == s[::-1]: return s l, ms = len(s), '' if l < 2: return s # 比第一行更优点 #l, m, ms = len(s), 1, s[0] # m 最大长度 ms 最长子串 for i in range(l): ...
def longestPalindrome(self, s): ans = '' max_len = 0 n = len(s) DP = [[False] * n for _ in range(n)] # 字符串长度为1 for i in range(n): DP[i][i] = True max_len = 1 ans = s[i] # 字符串长度为2 for i in range(n-1): ...
letterthatwas added in t.题目14:409.LongestPalindromeGivenastringwhichconsistsoflowercaseoruppercaseletters,findthelengthofthelongestpalindromesthatcanbebuiltwiththoseletters. EDX Python WEEK 1 problem 3 Longest substring_ Answer Writeaprogramthatprintsthelongestsubstringofs inwhichthelettersoccur in alphabetica...