leetcode.cn/problems/lo 解题思路 回文串只有中间的字符可以是单个的,其余的必须是双数,所以我们先遍历输入的字符串,将它存放在Map<字符,数目>中(由于区分大小写,不然可以借鉴之前的默认27个字母的数组减少空间复杂度) 解题方法 俺这版 class Solution { public int longestPalindrome(String s) {
409. Longest Palindrome FindTabBarSize Given a stringswhich consists of lowercase or uppercase letters, return the length of thelongestpalindromethat can be built with those letters. Letters arecase sensitive, for example,"Aa"is not considered a palindrome. Example 1: Input:s = "abccccdd"Output...
*/publicstaticStringlongestPalindrome(String s){if(s==null||s.length()<2){returns;}int maxLength=0;String longest=null;int length=s.length();boolean[][]table=newboolean[length][length];// 单个字符都是回文for(int i=0;i<length;i++){table[i][i]=true;longest=s.substring(i,i+1);ma...
题目地址:https://leetcode.com/problems/longest-palindrome/ Difficulty: Easy 题目描述 Given a string which consists of lowercase or uppercase letters, find the length of the longest palindromes that can be built with those letters. This is case sensitive, for example “Aa” is not considered a...
【leetcode】409. Longest Palindrome problem 409. Longest Palindrome solution1: classSolution {public:intlongestPalindrome(strings) { map<char,int>temp;for(auto it:s) temp[it]++;inteven =0, odd =0, mid=false;for(auto it=temp.begin(); it!=temp.end(); ++it)...
One longest palindrome that can be built is"dccaccd", whose length is 7. classSolution {publicintlongestPalindrome(String s) {if(s ==null|| s.length() == 0) {return0; } Map<Character, Integer> map =newHashMap<>();for(charc : s.toCharArray()) { ...
One longest palindrome that can be built is"dccaccd", whose length is 7. 1publicclassSolution {2publicintlongestPalindrome(String s) {3if(s==null|| s.length()==0)return0;4int[] count =newint[52];5for(inti=0; i<s.length(); i++) {6charc =s.charAt(i);7if(c < 'a') cou...
LeetCode算法题-Longest Palindrome(五种解法) 这是悦乐书的第220次更新,第232篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第87题(顺位题号是409)。给定一个由小写或大写字母组成的字符串,找到可以用这些字母构建的最长的回文长度。这是区分大小写的,例如“Aa”在这里不被视为回文。例如:...
参考:LeetCode:Longest Palindromic Substring 最长回文子串 - tenos中的方法4 动态规划 AC代码: 代码语言:javascript 代码运行次数:0 classSolution{public:stringlongestPalindrome(string s){constint len=s.size();if(len<=1)returns;bool dp[len][len];//dp[i][j]表示s[i..j]是否是回文memset(dp,0,...
解题:参考网上大神做法,解题如下: classSolution:defget_palindromic(self, s, k, l): s_len=len(s)whilek >= 0andl < s_lenands[k] ==s[l]: k-= 1l+= 1returns[k+1:l]deflongestPalindrome(self, s): L_palindromic=''foriinrange(len(s)): ...