Github 同步地址: https://github.com/grandyang/leetcode/issues/1027 参考资料: https://leetcode.com/problems/longest-arithmetic-subsequence/ https://leetcode.com/problems/longest-arithmetic-subsequence/discuss/274611/JavaC%2B%2BPython-DP LeetCode All in One 题目讲解汇总(持续更新中...)...
Asubsequenceis an array that can be derived from another array by deleting some or no elements without changing the order of the remaining elements. A sequenceseqis arithmetic ifseq[i + 1] - seq[i]are all the same value (for0 <= i < seq.length - 1). Example 1: Input:nums = [3...
Given an integer array arr and an integer difference, return the length of the longest subsequence in arr which is an arithmetic sequence such that the difference between adjacent elements in the subsequence equals difference. Example 1: Input: arr = [1,2,3,4], difference = 1 Output: 4 Ex...
Given an array A of integers, return the length of the longest arithmetic subsequence in A. Recall that a subsequence of A is a list A[i_1], A[i_2], …, A[i_k] with 0 <= i_1 < i_2 < … < i_k <= A.length - 1, and that a sequence B is arithmetic if B[i+1] -...
Explanation: The longest arithmetic subsequence is [7,5,3,1]. 很巧妙的算法,但是不是我想的 枯了 class Solution { public: int longestSubsequence(vector<int>& arr, int difference) { int ans=0; map<int,int>mp; for(auto x:arr){
LeetCode 300. Longest Increasing Subsequence 程序员木子 香港浸会大学 数据分析与人工智能硕士在读 来自专栏 · LeetCode Description Given an unsorted array of integers, find the length of longest increasing subsequence. Example: Input: [10,9,2,5,3,7,101,18]Output: 4Explanation: The ...
| LeetCode:674.最长连续递增序列,相信结合视频再看本篇题解,更有助于大家对本题的理解。思路本题相对于昨天的动态规划:300.最长递增子序列最大的区别在于“连续”。本题要求的是最长连续递增序列动态规划动规五部曲分析如下:确定dp数组(dp Java Python3 C++ 数组 11 2.1K 2...
1. Description Longest Increasing Subsequence 2. Solution 解析:Version 1,最长递增子序列,典型的动态规划问题,定义状态:以nums[i]作为结尾元素的最长递增子序列的长度,状态转移方程:遍历nums[i]之前的元素nums[j],如果nums[i] > nums[j],则其最长递增子序列的长度为max(dp[i], dp[j] + 1),遍历之后,可...
https://discuss.leetcode.com/topic/28738/java-python-binary-search-o-nlogn-time-with-explanation 解法有点怪。画了好长一段时间来理解。 tails[i] 描述的是 length = i + 1 的sub increasing sequence 中最小的值。只有这个最小,才有可能接上更多的数,使得总长度最大。
参考:https://leetcode.com/problems/longest-arithmetic-subsequence/discuss/274611/JavaC%2B%2BPython-DP""" from typing import Listclass Solution:def longestArithSeqLength(self, A: List[int]) -> int: dp = {} for i in range(len(A)):...