下面是一个示例代码，用于说明这个构造函数的使用：```class Node {public: int val; Node* next;};class Mystack {public: Node* top; int size; Mystack(const int& num, int arr[]) { top = nullptr; size = num; for (int i = 0; i num; i++) { ...
voidassign(ListNode*&head,intbh){ if(head==nullptr) return; if(head->val==bh){ ListNode*temp=head; head=head->next; deletetemp; } else{ ListNode*curr=head; while(curr->next!=nullptr&&curr->next->val!=bh){ curr=curr->next; } if(curr->next!=nullptr){ ListNode*temp=curr->next; ...
复制 struct ListNode{int val;//当前结点的值ListNode*next;//指向下一个结点的指针ListNode(int x):val(x),next(NULL){}//初始化当前结点值为x,指针为空}; 如何向ListNode中插入新的结点:从键盘输入 代码语言:javascript 复制 ListNode*temp1=newSolution::ListNode(0);//创建新元素,ListNode*l1=temp1;//...
}elementLList::DeleteHead(){// PRE: the N. O. LList is valid and not empty// POST: the N. O. LList is unchanged, except that the// listnode at the head end of the list has been// deleted, and its data element has been// returnedlistnode * temp; element thing; ...