1:List<string>转List<int> publicList<int> ListConvert(List<string>strlist) { List<int> intlist =null;try{ intlist= strlist.Select<string,int>(a => {returnConvert.ToInt32(a); }).ToList(); }catch(Exception) { intlist=null; }returnintlist; } 2:拼接字符串转List<int> List<int> ...
一种常见的方法是使用循环遍历String列表,将每个String对象转化为int类型,并将转化后的int值添加到一个新的int列表中。下面是一个示例代码: List<String>strList=Arrays.asList("1","2","3","4","5");List<Integer>intList=newArrayList<>();for(Stringstr:strList){intList.add(Integer.parseInt(str));...
varlist = (new[]{"1","2","3"}).ToList();varnewlist = list.Select<string,int>(x =>Convert.ToInt32(x)); List<int> 转List<string> List<int> list =newList<int>(newint[] {1,2,3} ); List<string> newList = list.ConvertAll<string>(x => x.ToString());...
List<Integer>intList=newArrayList<>(); 1. 步骤3:遍历String类型的List 接下来,我们需要遍历String类型的List,将每一个String都转换为Integer。 for(Stringstr:stringList){// 待添加代码} 1. 2. 3. 步骤4:将String转换为Integer 在遍历过程中,我们需要将每一个String类型的元素转换为Integer类型。 Integernum...
publicstaticvoidmain(String[]args){List<String>codes=newArrayList<String>();codes.add("1");codes.add("2");codes.add("3");codes.add("4");codes.add("5");codes.add("6");for(String code:codes){System.out.println("这是String类型:"+code);}System.out.println("+++++++++++++++++...
List<int> 转 string : list<int>:1,2,3,4,5,6,7转换成字符串:“1,2,3,4,5,6,7” List<int>list=newList<int>(){1,2,3,4,5,6,7};string depaid=string.Join(",",list); string 转 List<int>: string s="1, 2, 3";List<string>list=newList<string>(s.Split(newstring[]{",...
观察是否将列表和非列表的类型相连。观察是否将列表和非列表的类型相连。观察是否将列表和非列表的类型...
//请参考：string a = "1,2,3,4,5";List<int> list = a.Split(new string[] { "," }, StringSplitOptions.RemoveEmptyEntries).Cast<int>().ToList<int>();//欢迎追问。
1 List<string> 转 List<int> 1varstrList =newList<string>{"1","2","3"};2varintList = strList.Select<string,int>(x =>Convert.ToInt32(x)); 2 List<int> 转 List<string> 1List<int> intList =newList<int> {1,2,3};2List<string> strList = intList.ConvertAll<string>(x => ...
var newlist = list.Select<string,int>(x =>Convert.ToInt32(x)); List<int> 转List<string> List<int> list = new List<int>(new int[] { 1,2,3 } ); List<string> newList = list.ConvertAll<string>(x => x.ToString());