# Define a function that squares a numberdefsquare(x):returnx**2# List of numbersnumbers=[1,2,3,4,5]# Apply the square function to each element in the listsquared_numbers=[square(x)forxinnumbers]# Print the list of squared numbersprint(squared_numbers) Copy Output: [1, 4, 9, 16,...
Finding an integer’s square root is the opposite of square numbers. Therefore, the square value of a number is achieved by multiplying it by itself. In contrast, you can get the square root of any given integer by looking for a number that shows the original value when squared. Square R...
Use list comprehension to create a list of squares. Therange()function generates a number range for this task. For example: squares_list = [number**2 for number in range(0, 10)] print(squares_list) The resulting list contains squared numbers between zero and ten. Filtering a List Add a...
# task 1: Convert the list of numbers (nums here) to their squares. squared_numbers = [] #TODO complete this line print(squared_numbers) # should output: [1, 4, 9, 16, 25, 36, 49, 64, 81] # task 2: Extract even numbers from the list nums...
sum_of_squared_numbers=sum(squared_numbers) 1. 在上述代码中,我们使用sum()函数对squared_numbers中的所有元素进行求和,并将结果保存在sum_of_squared_numbers变量中。 3. 完整代码 下面是整个实现的完整代码: numbers=[1,2,3,4,5]squared_numbers=[]fornuminnumbers:squared_numbers.append(num**2)sum_of...
List<int> squaredNumbers = numbers.map((number) => number * number).toList(); print('原始数字列表:$numbers'); print('每个数字的平方列表:$squaredNumbers'); 1. 2. 3. 4. 5. map方法就像是 List 的魔法师,可以将每个元素进行转换,创造出一个全新的 List。
# Create a list of numbers from 1 to 10 numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] # Use a list comprehension to create a new list with the even numbers squared and the odd numbers cubed result = [x**3 if x % 2 == 1 else x**2 for x in numbers] print(result)...
List<int>numbers=[1,2,3,4,5];List<int>squaredNumbers=numbers.map((number)=>number*number).toList();print('原始数字列表:$numbers');print('每个数字的平方列表:$squaredNumbers'); map方法就像是 List 的魔法师,可以将每个元素进行转换,创造出一个全新的 List。
Square number is the result of multiplying a number by itself. If n is a number, then its square is n^2. Also, square root of n^2 is equal to n. List of square numbers at BYJU’S.
Here is an example of a lambda function: Python Python 1 2 3 4 5 square_function = lambda number: number ** 2 squared_numbers = [square_function(number) for number in numbers] print(squared_numbers) Use code with caution. Learn more This code creates a lambda function called square_fu...