1.遍历MapMap<Integer,String> map=newHashMap<>(); map.put(1,"a"); map.put(2,"b"); map.put(3,"c");// Map.keySet遍历for(Integerk : map.keySet()) {System.out.println(k+" ==> "+map.get(k)); } map.keySet().forEach(k ->System.out.println(k+" ==> "+map.get(k)))...
packagecom.entify;importjava.util.HashMap;importjava.util.Iterator;importjava.util.Map;publicclassDemo{publicstaticvoidmain(String[]args){Map<Integer,String>map=newHashMap<>();map.put(2,"b");map.put(1,"b");map.put(1,"a");map.put(4,"b");map.put(3,"c");System.out.println(...
System.out.println("---map---"); System.out.println("---循环遍历键取值---"); for (Map.Entry<Integer, String> entry : m.entrySet()) { System.out.println(entry.getKey() + " " + entry.getValue()); } System.out.println("---根据键取值(键正好为整数)---"); for (int i = ...
如果只需要map中的键或者值,你可以通过keySet或values来实现遍历,而不是用entrySet。 1. Map<Integer, Integer> map = new HashMap<Integer, Integer>(); 2. 3. //遍历map中的键 4. 5. for (Integer key : map.keySet()) { 6. 7. "Key = " + key); 8. 9. } 10. 11. //遍历map中的值...
Map的三种遍历方式: publicstaticvoidmain(String[]args){Map<String,Integer>map=newHashMap<>();map.put("孙悟空",1);map.put("唐三藏",2);map.put("猪八戒",3);map.put("沙悟净",4);Set<String>keySet=map.keySet();for(String key:keySet){Integer value=map.get(key);System.out.println("...
Map<String, Integer> m1 = new HashMap<String, Integer>();m1.put("a", 3);m1.put("b", 1);m1.put("c", 1);m1.put("d", 2);list1.add(m1);Map<String, Integer> m2 = new HashMap<String, Integer>();m2.put("a", 34);m2.put("b", 13);m2.put("c", 12...
Map<String, Integer> m1 = new HashMap<String, Integer>();m1.put("a", 3);m1.put("b", 1);m1.put("c", 1);m1.put("d", 2);list1.add(m1);Map<String, Integer> m2 = new HashMap<String, Integer>();m2.put("a", 34);m2.put("b", 13);m2.put("c", 12...
遍历嵌套的Map<Integer, List<abc>>可以使用递归的方式进行操作。下面是一个完善且全面的答案: 遍历嵌套的Map<Integer, List<abc>>的步骤如下: 1. 首先,...
其实Map和List基本差不多,我们看看Map的使用情况: Map<Integer, String> platformMap = new HashMap<>();platformMap.put(1, "掘金");platformMap.put(2, "知乎");platformMap.put(3, "微信公账号");// Map情况1:for (Map.Entry<Integer, String> entry : platformMap.entrySet()) {Integer entryKey =...