2019-12-02 16:03 −# LRU Algorithm $$ Time Limit: 1000 ms\quad Memory Limit: 524288 kB $$ ## 题意 给出 $n$ 个数字和 $m$ 次查询。 每次询问中,给出 $L$ 表示 $LRU$ 中缓存器的大小,再给出 $L$ 个数字,问对 $n$ 个数... ...
Fast access:The cache insert and lookup operations need to be fast preferably O(1) time. Entry replacement algorithm:When the cache is full, the less useful cache entries are purged from cache. The algorithm to replace these entries is Least Recently Used (LRU) - or the cache entries which...
* 列表大小大于容量时,清理头结点 */@OverrideprotectedbooleanremoveEldestEntry(Map.Entry<K,V>eldest){returnsize()>capacity;}publicstaticvoidmain(String[]args){ManualLruAlgorithm<String,String>lruCache=newManualLruAlgorithm<>(3);lruCache.put("a","a");lruCache.put("b","b");lruCache.put("c","...