https://leetcode.com/problems/palindrome-linked-list/ 思路1:遍历一次链表,用一个数组存储链表节点值,然后用双指针法判断数组是否是回文的。需要额外O(n)的空间。 C++ classSolution{public:boolisPalindrome(ListNode* head){if(!head || !head->next)returntrue; vector<int> vec;while(head) { vec.push...
然后把前半截的node values逐个push到一个stack里。然后从后半截开始逐个比较node value和stack[-1]。注意list长度为奇偶的两种情况。奇数时,先pop掉中间一个。 1classSolution(object):2defisPalindrome(self, head):3"""4:type head: ListNode5:rtype: bool6"""7ifnotheadornothead.next:8returnTrue910m ...
234. Palindrome Linked List 難度 easy 個人範例程式碼 – Deque (比較進階),空間 O(N) # Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def isPalindrome(self, head: Optional[ListNode]...
Can you solve this real interview question? Palindrome Linked List - Given the head of a singly linked list, return true if it is a palindrome or false otherwise. Example 1: [https://assets.leetcode.com/uploads/2021/03/03/pal1linked-list.jpg] Inpu
LeetCode: 234. Palindrome Linked List 题目描述 Given a singly linked list, determine if it is a palindrome. Example 1: Input: 1->2 Output: false 1. 2. Example 2: Input: 1->2->2->1 Output: true 1. 2. Follow up: Could you do it in O(n) time and ...
我的github连接:https://github.com/princewen/leetcode_python 21. Merge Two Sorted Lists Merge Two Sorted Lists 很简单的链表拼接题,但是要注意两个地方 1、返回值要返回head.next 2、无需判断循环后哪个不为空,or返回第一个为真的值 # Definition for singly-linked list. ...
【LeetCode】234 Palindrome Linked List Total Accepted: 1116 Total Submissions: 4295 My Submissions Question Solution Given a singly linked list, determine if it is a palindrome. Follow up: Could you do it in O(n) time and O(1) space?
My code: importjava.util.Stack;/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */publicclassSolution{publicbooleanisPalindrome(ListNode head){if(head==null||head.next==null)returntrue;ListNode slow=...
Palindrome Linked List 判断链表是否回文 分析:将链表从中间截断,若后半部与前半部相同则回文成立 privatebooleanisPalindrome(ListNode head){ListNode fast=head;ListNode slow=head;while(fast!=null&&fast.next!=null){//慢走1快走2,当快到终点时,慢在中点fast=fast.next.next;slow=slow.next;}if(fast!=nul...
LeetCode problem solving notes. Determine whether a linked list is a palindrome linked list. First convert the linked list into an array, and then judge whether the array is a palindrome array.