[LeetCode] 707. Design Linked List 设计链表 Design your implementation of the linked list. You can choose to use the singly linked list or the doubly linked list. A node in a singly linked list should have two attributes:valandnext.valis the value of the current node, andnextis a pointe...
Given a linked list, return the node where the cycle begins. If there is no cycle, returnnull. Follow up: Can you solve it without using extra space? Solution: Discuss上的分析:Suppose the first meet at stepk,the length of the Cycle isr. so..2k-k=nr,k=nrNow, the distance between ...
Delete N Nodes After M Nodes of a Linked List 参考资料: https://leetcode.com/problems/remove-zero-sum-consecutive-nodes-from-linked-list/ https://leetcode.com/problems/remove-zero-sum-consecutive-nodes-from-linked-list/discuss/366350/C%2B%2B-O(n)-(explained-with-pictures) https://leetcod...
Can you solve this real interview question? Intersection of Two Linked Lists - Given the heads of two singly linked-lists headA and headB, return the node at which the two lists intersect. If the two linked lists have no intersection at all, ...
* TreeNode(int x) : val(x), left(NULL), right(NULL) {} * };*/classSolution {public: TreeNode* prev =NULL;voidflatten(TreeNode*root) {//using this solution:https://leetcode.com/problems/flatten-binary-tree-to-linked-list/discuss/36977/My-short-post-order-traversal-Java-solution-for...
Rotate List Odd Even Linked List 参考资料: https://discuss.leetcode.com/topic/110475/c-solution-o-1-space-9ms 本文转自博客园Grandyang的博客,原文链接:[LeetCode] Split Linked List in Parts 拆分链表成部分 ,如需转载请自行联系原博主。
lintcode:(35) Reverse Linked List Reverse a linked list. Example For linked list 1->2->3, the reversed linked list is 3->2->1 Challenge Reverse it in-place and in one-pass 题解1 - 非递归 联想到同样也可能需要翻转的数组,在数组中由于可以利用下标随机访问,翻转时使用下标即可完成。而在单...
// https://discuss.leetcode.com/topic/53812/using-reservoir-sampling-o-1-space-o-n-time-complexity-c/2 /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } ...
https://leetcode.com/problems/palindrome-linked-list/discuss/64501/Java-easy-to-understand https://github.com/abesft/leetcode/blob/master/234PalindromeLinkedList/234PalindromeLinkedList.cpp#include <iostream> #include<vector> using namespace std; class Solution { public: bool isPalindrome(ListNode* ...
解法二中提到如果用先序遍历的话,会丢失掉右孩子,除了用后序遍历,还有没有其他的方法避免这个问题。在Discuss又发现了一种解法,参考这里。 为了更好的控制算法,所以我们用先序遍历迭代的形式,正常的先序遍历代码如下, publicstaticvoidpreOrderStack(TreeNoderoot){if(root==null){return;}Stack<TreeNode>s=newSta...