https://leetcode.com/problems/palindrome-linked-list/ 思路1:遍历一次链表,用一个数组存储链表节点值,然后用双指针法判断数组是否是回文的。需要额外O(n)的空间。 C++ classSolution{public:boolisPalindrome(ListNode* head){if(!head || !head->next)returntrue; vector<int> vec;while(head) { vec.push...
思路很清晰,代码直接写在leetcode网站上了,没有调试,一次性AC通过,很有成就感 boolisPalindrome(ListNode*head) {if(head == nullptr || head->next ==nullptr)returntrue;//寻找中间结点ListNode *slow =head; ListNode*fast =head;while(fast->next != nullptr && fast->next->next !=nullptr) { slow=...
Can you solve this real interview question? Palindrome Linked List - Given the head of a singly linked list, return true if it is a palindrome or false otherwise. Example 1: [https://assets.leetcode.com/uploads/2021/03/03/pal1linked-list.jpg] Inpu
* Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: bool isPalindrome(ListNode* head) { if(head == NULL || head->next == NULL) return true; stack<int> st; List...
LeetCode: 234. Palindrome Linked List 题目描述 Given a singly linked list, determine if it is a palindrome. Example 1: Input: 1->2 Output: false 1. 2. Example 2: Input: 1->2->2->1 Output: true 1. 2. Follow up: Could you do it in O(n) time and ...
我的github连接:https://github.com/princewen/leetcode_python 21. Merge Two Sorted Lists Merge Two Sorted Lists 很简单的链表拼接题,但是要注意两个地方 1、返回值要返回head.next 2、无需判断循环后哪个不为空,or返回第一个为真的值 # Definition for singly-linked list. ...
My code: importjava.util.Stack;/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */publicclassSolution{publicbooleanisPalindrome(ListNode head){if(head==null||head.next==null)returntrue;ListNode slow=...
Palindrome Linked List 判断链表是否回文 分析:将链表从中间截断,若后半部与前半部相同则回文成立 privatebooleanisPalindrome(ListNode head){ListNode fast=head;ListNode slow=head;while(fast!=null&&fast.next!=null){//慢走1快走2,当快到终点时,慢在中点fast=fast.next.next;slow=slow.next;}if(fast!=nul...
LeetCode problem solving notes. Determine whether a linked list is a palindrome linked list. First convert the linked list into an array, and then judge whether the array is a palindrome array.
Given a singly linked list, determine if it is a palindrome. Follow up: Could you do it in O(n) time and O(1) space? 反转链表 复杂度 时间O(N) 空间 O(1) 思路 两个指针都从头出发,快指针每次两步,慢指针每次一步,这样快指针的下一个或下下个为空时,慢指针就在链表正中间那个节点了(如...