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Coding Interviews 3 Linked List Linked list is a one of the most important topic in interviews. Because it uses dynamic memory and short lines can finish its implement. It is often used as test question. Here is the structure of a node of linked list typedefstructNode {intval;structNode*pn...
Btw, if you get this question asked in the real interview, you would be most likely asked to reverse the linked list using recursion now. So, wait for another article to see that solution or check out theCracking the Coding Interviewbook, which contains a solution to this problem along wit...
1. http://www.programcreek.com/2012/12/leetcode-linked-list-cycle/ 2. http://www.cnblogs.com/hiddenfox/p/3408931.html 3. http://yucoding.blogspot.com/2013/10/leetcode-question-linked-list-cycle.html
*The detection of loops in graphs/linked lists is a classic interview question, a good solution to which is Floyd's Algorithm, also known at the "Tortoise and Hare" approach, and this is to move two pointers over the list at different speeds and see if they ever end up at the same ...
Any of available paths will be sufficient for us to answer the main question — binary tree contains all nodes in provided linked list. https://gist.github.com/RakhmedovRS/e9a1695b8e14c2de165fa36489a4b454 The full solution https://gist.github.com/RakhmedovRS/db8111d9d89a0ba2d910f5...
Each item in the list is a node, and a node contains two things: the value itself, and a reference to the next node in the list. Why would you do this instead of use an array? Well that’s a good question. It depends on what kind of array you’ve got. In JavaScript, we have...
End of part 2 In part 3 of this article I plan to answer the critical question: how does it all work? For the impatient, check out the implementation here inList.h.
This question is a pretty easy one. The first approach that comes to mind is to pick one element from one list, then traverse through the other list, and keep adding to output lists if necessary. But, can we do better? Yes. We can use hashing. Let us have a glance at the approache...
which can be caused by either de novo mutations or maternally inherited variants. Analyses of new large datasets of population variation have called into question a few of these gene associations9, although most remain robust. Importantly, mutations in the same gene can cause more than one conditi...