Search in Rotated Sorted Array II 解答 解法1 // 时间复杂度O(n), 空间复杂度O(1) class Solution { public: bool search(vector<int>& nums, int target) { int lo = 0; int hi = nums.size(); while (lo != hi) { int mid = lo + (hi - lo) / 2; if (target == nums[mid]) ...