Homework Statement Given the circle (x+1)^2 + (y-3)^2 = 25, determine the equations of the tangents to the circle with the slope -3/4.Homework Equations y...
c) slope of line R from center of circle (0,0) to point in part B is (x - 0) / (y - 0) = - mr^2/b / (r^2/b) = - mr^2/b * (b/r^2) = -m ** the slope of this line is -m, this line is perpendicular to the tangent line ( with equation y = mx + b ...
Let the equation of the tangent line be y= -x +b. Substituting this into the equation of the circle: 2x^2- 2bx+b^2-4=0 . Since the line is tangent to the circle, we have △=(-2b)^2-4*2(b^2-4)=0 Solving for b: b =±2 2. So the equation of the tangent line is ...
Slope of a line tangent to a circle – direct versionA circle of radius 1 centered at the origin consists of all points (x, y) for which x2 + y2 = 1. This equation does not describe a function of x (i.e. it cannot be written in the form y = f(x)). Indeed, any vertical...
Recall from geometry that the line draw tangent to a circle is perpendicular to the radius line drawn to the point of tangency.Use this fact to find the equation of the line tangent to the circle x^2 + y^2 = 25 at (-3,4).
The line tangent to the circle x^2+y^2=1 at (35,45 ) is perpendicular to the radius drawn from the point of tangency.Note that the equation x^2+y^2=1 represents a circle centered at the origin with a radius of one unit.The line containing the radius from point (35,45 ) has...
equation of the circle is(x -4)2+-|||-(y-4)2=16or(x-1)2+(y+1)2=1.-|||-Method 2:-|||-Let the equation of the circle be-|||-(x-a)2+(y-b)2=r2-|||-Since the circle is tangent to both axis-|||-a2=b2=r2-|||-(1)-|||-Since the center of the circle is ...
Equation of tangent to the circle x2+y2=50 at the point where the line x+7=0 meets the circle A7x+y=50 Bx+7y=50 Cx±7y=50 D7x±y=50Submit If the tangents are drawn from any point on the line x+y=3 to the circle x2+y2+9, then the chord of contact always passes through...
The value of {eq}\tan \theta {/eq} of the line is the slope of the tangent and in the expression above, the right-hand side is the derivative of the function at that point.Answer and Explanation: We need to find the equation of the line tangent to the ...
wheremis the slope of the tangent line that passes through the point(x1,y1). Another way to determine the equation of the tangent line is the slope-intercept form. Answer and Explanation:1 First, compute the slope ofy=2xx+1: m=dydx=2(x+1)2 ...