4. 单选题limlimits_(x→a)((sin)x-(sin)a)/(x-a)=( )A (sin)aB (tan)aC (cos)aD (cot)a
Stimulated by Jakobsen and Pellegrini's Love the Sin: Sexual Regulation and the Limits of Religious Tolerance, this essay is an effort to extend the value of their contribution by including a psychoanalytic perspective within its purview. My intent is to bring psychoanalytic readers into this ...
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While evaluating the limit, the indeterminate forms need to be eliminated. For that, we apply certain rules like L'hospitals rule, algebraic methods and trigonometric formulas. Some important formulas used in the limits are: limx→0sinxx=1sin(π2−x)=cosx ...
(3) 当 x → 0 时,sin x ∼ x,ln x → -∞。利用洛必达法则,原极限可化为 lim_(x → 0) -x(ln x)^2 cos x,由于 x(ln x)^2 → 0,cos x → 1,因此极限值为 0。 (4) 当 x → 0 时,sin 3x ∼ 3x,tan 2x ∼ 2x,ln(1+x) ∼ x。利用等价无穷小替换,原极限...
=limlimits_(x→ 0) (tan x-sin x)(tan x-sin x) ⋅ 12=12. 首先,将极限中的函数分子有理化,并化简分母;然后,利用等价无穷小化简极限,即可求解.结果一 题目 求极限lim x→0+(x的x次 方) 答案 lim(x->0)x^x =(x->0)e^{limxlnx}=(x->0)e^{lim(lnx)/(1/x)} (用罗...
Homosexuals, Heretics, and the Practice of Freedom Commentary on Love the Sin: Sexual Regulation and the Limits of Religious Tolerance by Janet R. Jakobsen and Ann PelligriniHere I construe Janet R. Jakobsen and Ann Pellegrini's proposal to protect freedom of sexual expression among consenting ...
Find the limit \lim_{t\rightarrow 0} (e^{-7t} i + \frac{t^2}{\sin^2 t} j + \tan(7t) k) Find the limit \lim_{t\rightarrow 2} \frac{t^2-4}{t^3-8} Find the limit. \lim_{t\rightarrow 0} \frac{(sin5t)^2}{(t^2)(cos4t)} Find the limit. \lim_{f(x...
Evaluate the limit: \lim_{\theta \rightarrow \frac{\pi}{2\frac{cos^2 \theta}{1-sin \theta} Evaluate the limit. lim_x to 4 3(ln(9x+10)+1) / 4((2x+2)^1 / 3 + 1) Evaluate the limit \lim_{x\rightarrow 0} \frac{\sqrt{4-x^2} - 2}{x} Evaluate the limit...
所以,lim_(x → 0) (tan x - sin x)/(x sin x (1 - cos x)) = 0。 该极限问题可以通过洛必达法则求解。由于分子分母在x趋近于0时都趋近于0,满足洛必达法则的条件。对分子分母分别求导,得到新的极限表达式。最终计算得到极限值为0。反馈 收藏 ...