levelNodes.add(node.left);if(node.right!=null) levelNodes.add(node.right); res.add(node.val); } list.addAll(levelNodes); ans.add(res); }returnans; } }
leetcode---Binary Tree Level Order Traversal II Given a binary tree, return thebottom-up level ordertraversal of its nodes' values. (ie, from left to right, level by level from leaf to root). For example: Given binary tree{3,9,20,#,#,15,7}, 3 / \ 9 20 / \ 15 7 return its...
题目:Binay Tree Level Order Traversal Given a binary tree, return the level order traversal of its nod Linux云计算网络 2018/01/11 4870 LeetCode 103 Binary Tree Zigzag Level Order Traversal 编程算法 Given a binary tree, return the zigzag level order traversal of its nodes' values. (ie, fro...
Binary Tree Level Order Traversal Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example: Given binary tree [3,9,20,null,null,15,7], 代码语言:javascript 代码运行次数:0 运行 AI代码解释 3/\920/\157 return it...
Leetcode: Binary Tree Level Order Traversal II,题目:Givenabinarytree,returnthebottom-uplevelordertraversalofitsnodes'values.(ie,fromlefttoright,levelbylevelfromleaftoroot).Forexample:Givenbinarytree{3,9,20,#,#,15,7
[LeetCode] 103. Binary Tree Zigzag Level Order Traversal,Givenabinarytree,returnthe zigzaglevelorder traversalofitsnodes'values.(ie,fromlefttoright,thenrighttoleftforthenextleveland
【Description】 Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example: Given binary tree [3,9,20,null,null,15,7], 3 / 9 20 / 15 7 return its level order traversal as: ...
LeetCode笔记:102. Binary Tree Level Order Traversal Cloudox_关注IP属地: 广东 2017.11.21 10:17:33字数484阅读504 问题: Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example: Given binary tree [3,9,20,null,...
time: visit all nodes eventually, O(n), space O(n) Note1: not multiplying on overall level sum. Only multiply level with single value at this level. Note2:top->bottom is not necessary: there is not need of passing added object into next level. BFS bfs, queue, 处理queue.size(). us...
给定一个 N 叉树,返回其节点值的层序遍历。(即从左到右,逐层遍历)。 Given an n-ary tree, return thelevel ordertraversal of its nodes' values. 例如,给定一个3叉树: 返回其层序遍历: [ [1], [3,2,4], [5,6] ] 示例2: Nary-Tree input serialization is represented in their level order ...