AI检测代码解析 1/**2* Definition for a binary tree node.3* public class TreeNode {4* int val;5* TreeNode left;6* TreeNode right;7* TreeNode() {}8* TreeNode(int val) { this.val = val; }9* TreeNode(int val, TreeNode left, TreeNode right) {10* this.val = val;11* this....
Thereare two left leavesinthe binary tree,withvalues9and15respectively.Return24. packageleetcode.easy; /** * Definition for a binary tree node. public class TreeNode { int val; TreeNode * left; TreeNode right; TreeNode(int x) { val = x; } } */ publicclassSumOfLeftLeaves{ publicints...
Find the sum of all left leaves in a given binary tree think about this, when we reached leaf, how are we gonna to know if it is left leaf or not? of course we can modify the iterate version of preorder traverse, it’s very simple. but how are we gonna do it recursively? AI检...