1/**2* Definition for a binary tree node.3* public class TreeNode {4* int val;5* TreeNode left;6* TreeNode right;7* TreeNode() {}8* TreeNode(int val) { this.val = val; }9* TreeNode(int val, TreeNode left, TreeNode right) {10* this.val = val;11* this.left = left;1...
这个题的思路其实跟[LeetCode] 199. Binary Tree Right Side View_ Medium tag: BFS, Amazon里面我提到的left side view一样的思路, 只是返回的时候返回最后一个元素即可. 1. Constraints 1) root cannot be None, 所以edge case就是 1 2, Ideas BFS: T: O(n), S: O(n) n is the number of the...
404. Sum of Left Leaves Easy Find the sum of all left leaves in a given binary tree. Example: 3 /\ 920 /\ 157 Thereare two left leavesinthe binary tree,withvalues9and15respectively.Return24. packageleetcode.easy; /** * Definition for a binary tree node. public class TreeNode { int...
Find the sum of all left leaves in a given binary tree think about this, when we reached leaf, how are we gonna to know if it is left leaf or not? of course we can modify the iterate version of preorder traverse, it’s very simple. but how are we gonna do it recursively? class...
404. Sum of Left Leaves Find the sum of all left leaves in a given binary tree. Example: ...leetcode1 two_sum ...相关文章C 报错 [Error] lvalue required as left operand of assignment c++报错:lvalue required as left operand of assignment Solve error: lvalue required as left operand of ...