Since there is such an important conclusion, we can safely drop the first k/2 element in A, which are definitaly smaller than k-th element in the union of A and B. This is also true for the A[k/2-1] > B[k/2-1]
set_union 这个会把重复元素除掉,需要注意。 + View Code
1 -- set_intersection(交集) 2 -- set_union(并集) 3 -- set_difference(差集) 4 -- set_symeetric_difference(对称差集) 去重的unique。 classSolution{ public: vector<int>unique_element_in_vector(vector<int>&v){ vector<int>::iteratorvector_iterator; sort(v.begin(),v.end()); vector_ite...
class Solution { private val directions = arrayOf(intArrayOf(0, 1), intArrayOf(0, -1), intArrayOf(1, 0), intArrayOf(-1, 0)) fun findMaxFish(grid: Array<IntArray>): Int { val n = grid.size val m = grid[0].size var ret = 0 // 并查集 val helper = UnionFind(grid) /...
中频:动态规划(DP),扫描线(Sweep Line),字典树(Trie),并查集(Union Find),单调栈与单调队列(Monotone Stack/ Queue),TreeMap等 低频:Dijkstra,树状数组,线段树,最小生成树等… 4. 如何刷题:每个人的基础、学习习惯都不一样,以下是我个人的习惯。(注意: 我基本上每周都会花20-40小时刷题,而且我本身有朝九...
can not access to items of a paginated union query results I want to paginate a Union query result. I wrote this : Now I want to access result in the search blade template.Suppose I wrote this : But I got this error : That can not recognize $user and it's nam......
21. Merge Two Sorted Lists # 题目 # Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 题目大意 # 合
很多人连Segment Tree,BIT,Trie,Union Find这种数据结构都不懂,遇见就刷,自己想,怎么可能想的出来? 所以刷题最重要的,第一步,就是了解所有的数据结构,做题方法,基础算法。从基础数据结构HashMap,HashSet,到TreeSet,TreeMap,Deque,LinkedHashMap;到各种对刷题来说的基础算法,各种排序算法,DFS,BFS,Sliding Window...
https://leetcode.cn/problems/checking-existence-of-edge-length-limited-paths-ii/ 1697的在线版本,但难度完全不是一个次元。这道题需要对基础并查集模板的Union做改进,不能直接压缩路径,而是按秩序合并的同时,记录每条边的权重信息,查询时如果某个合并方向的权重不满足,就不能朝这个方向合并。
1679. Max Number of K-Sum Pairs # 题目 # You are given an integer array nums and an integer k. In one operation, you can pick two numbers from the array whose sum equals k and remove them from the array. Return the maximum number of operations you can