42. Trapping Rain Water Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,1,0,1,3,
AI代码解释 classSolution{publicinttrap(int[]height){int result=0;if(height.length==0)returnresult;int[]left_height_array=newint[height.length];int[]right_height_array=newint[height.length];int left_max=0;int right_max=0;left_height_array[0]=0;right_height_array[0]=0;for(int i=1;i...
换而言之,这种遍历的方法是遍历求每个横坐标单位上所能trap住的water,即 在这个单位横坐标上所能trap的water减去这个单位上竖条所占的面积: 代码: classSolution {publicinttrap(int[] height) {intwater=0;for(inti=0;i<height.length;i++){intmax_left=0;intmax_right=0;for(intj=i;j>=0;j--){ m...
https://oj.leetcode.com/problems/trapping-rain-water/ Trapping Rain Water Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,1,0,1,3,2,1,2,1], return...
LeetCode 42. Trapping Rain Water Python解法 解题思路: 本思路需找到最高点左右遍历,时间复杂度O(nlogn),以下为向左遍历的过程。 1. 将每一个点的高度和索引存成一个元组 (val, idx) 2. 找到最高的点(可能有多个,任取一个),记为 (now_
https://oj.leetcode.com/problems/trapping-rain-water/ 这道题使用单调队列能够O(n)时间解决。维护一个降序排列的单调队列。如果Ai>A[que.front]就说明能够使用que.front作为顶部计算一次积水。 当从0-n时,须注意队列中还有元素。需要反向再执行一次单调队列。但是只需要到之前队列的front的位置即可。
leetcode 42. Trapping Rain Water Hard descrition Given n non negative integers representing an elevation map where the width of each bar is 1, compute
Solution 解题描述 Trapping Rain Water 题解 题目来源:https://leetcode.com/problems/trapping-rain-water/description/ Description Givennnon-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. ...
https://leetcode-cn.com/problems/trapping-rain-water/ 题目内容 给定n 个非负整数表示每个宽度为 1 的柱子的高度图,计算按此排列的柱子,下雨之后能接多少雨水。 示例: 输入: [0,1,0,2,1,0,1,3,2,1,2,1] 输出: 6 思路 我们可以设置两个数组,left_height_array和right_height_array; ...
leetcode---Trapping Rain Water Givennnon-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given[0,1,0,2,1,0,1,3,2,1,2,1], return6....