第一部分---线段树:https://leetcode.com/tag/segment-tree/ 【218】The Skyline Problem 【307】Range Sum Query - Mutable 【308】Range Sum Query 2D - Mutable 【315】Count of Smaller Numbers After Self 【493】Reverse Pairs 【699】Falling Squares(我的线段树第一题,2019年1月24日) 在X 轴上落...
}publicsegmentNodebuildTree(int[] nums,intstart,intend){if(start > end)returnnull;else{segmentNodenode=newsegmentNode(start,end);if(start == end) node.sum = nums[start];else{intmiddle=start + (end - start) /2; node.left = buildTree(nums,start,middle); node.right = buildTree(nums,...
v=xuoQdt5pHj0&t=622s 这道题的另外一种解法就是Lazy Propagation in Segment Tree(线段树的惰性传播)。这个方法来源于leetcode的disscuss中,如下链接。 https://leetcode.com/problems/my-calendar-iii/discuss/214831/Python-13-Lines-Segment-Tree-with-Lazy-Propagation-O(1)-time 【实现】 惰性传播,(惰性...
用一个数据结构(比如TreeSet)维护当前的活动区间。每次扫描到一个事件时,更新该区间,检查是否存在重叠。 如何判断是否重叠: private boolean hasOverlap(TreeSet<int[]> activeIntervals) { int prevEnd = Integer.MIN_VALUE; // 初始化 prevEnd 为一个极小值 for (int[] interval : activeIntervals) { // ...
线段树（Segment Tree）（不常见，后续补充）定义：一种特殊的二叉树，用于高效处理数组区间的统计信息（...
才叫刷题。没有人一遍就会，大多数人都向快。直接做题，不管不顾基础知识。很多人连Segment Tree，BIT...
public boolean validTree(int n, int[][] edges) { UnionFind uf = new UnionFind(n); for (int[] edge : edges){ int p = edge[0]; int q = edge[1]; if (uf.find(p) == uf.find(q)) return false; else uf.union(p,q); ...
Segment Tree 307.Range-Sum-Query-Mutable (H-) 1526.Minimum-Number-of-Increments-on-Subarrays-to-Form-a-Target-Array (H-) 1649.Create-Sorted-Array-through-Instructions (H-) 1157.Online-Majority-Element-In-Subarray (H) 370.Range-Addition (H) 218.The-Skyline-Problem (H+) 699.Falling-Squa...
N/A Path Sum II.java Easy [Backtracking, DFS, Tree] Java 197 N/A Segment Tree Query II.java Medium [Binary Tree, DFS, Divide and Conquer, Lint, Segment Tree] Java 198 N/A Shortest Distance from All Buildings.java Hard [BFS] Java 199 N/A Brick Wall.java Medium [Hash Table] O(mn...
Topics ArrayBinary Indexed TreeSegment TreeSorting Companies Hint 1 What can you say about the position of the shortest person? If the position of the shortest person is i, how many people would be in front of the shortest person? Hint 2 Once you fix the position of the shortest per...