You are given therootof a binary search tree (BST) and an integerval. Find the node in the BST that the node's value equalsvaland return the subtree rooted with that node. If such a node does not exist, returnnull. Example 1: ...
700. Search in a Binary Search Tree Given the root node of a binary search tree (BST) and a value. You need to find the node in the BST that the node's value equals the given value. Return the subtree rooted with that node. If such node......
将所有节点值依次入队列,在入队列前先判断节点值是否等于val,等于就直接返回当前节点所在子树。 publicTreeNode searchBST(TreeNode root, intval) {if(root ==null|| root.val==val) {returnroot; } Queue<TreeNode> queue = new LinkedList<TreeNode>(); queue.offer(root);while(!queue.isEmpty()) { ...
Given the root node of a binary search tree (BST) and a value. You need to find the node in the BST that the node's value equals the given value. Return the subtree rooted with that node. If such node doesn't exist, you should return NULL. For example, Given the tree: 4 / \ ...
Given the root node of a binary search tree (BST) and a value. You need to find the node in the BST that the node's value equals the given value. Return the subtree rooted with that node. If such node doesn't exist, you should return NULL. ...
Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST. ...
Right } } // 没有找到值为 val 的结点,则返回空 return nil } 题目链接: Search in a Binary Search Tree : leetcode.com/problems/s 二叉搜索树中的搜索: leetcode-cn.com/problem LeetCode 日更第 89 天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满...
Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST. ...
Can you solve this real interview question? Binary Search Tree Iterator - Implement the BSTIterator class that represents an iterator over the in-order traversal [https://en.wikipedia.org/wiki/Tree_traversal#In-order_(LNR)] of a binary search tree (BST):
* Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */publicclassSolution{publicTreeNodelowestCommonAncestor(TreeNode root,TreeNode p,TreeNode q){if(root.val-p.val>0&&root.val-q.val...