Can you solve this real interview question? Search a 2D Matrix II - Write an efficient algorithm that searches for a value target in an m x n integer matrix matrix. This matrix has the following properties: * Integers in each row are sorted in ascendin
bottom=0, top = matrix[0].size() -1;for(inti =0; i < matrix.size(); ++i) {//对每一行进行二分查找boolf =binSearch(matrix[i], bottom, top, target);if(f)returntrue; }returnfalse; }boolbinSearch(vector<int>& arr,intsta,intend,int&target) {//如果二分查找到最后,判断是否找到目...
https://leetcode.com/problems/search-a-2d-matrix-ii/ 240. Search a 2D Matrix II Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integers in each column...
public: bool searchMatrix(vector<vector<int>>& matrix, int target) { if(matrix.empty()) return false; int rows=matrix.size(); int cols=matrix[0].size(); if(rows<1||cols<1) return false; int row=0; int col=cols-1; while(row<rows&&col>=0){//合法范围内查找target int candidate...
Leetcode 240. Search a 2D Matrix II 简介:具体思路就是每一行倒着扫,扫到第一个比target小的数就跳到下行,如果等于当然是直接返回true了,如果下一行还比target小就继续跳下一行,直到最后一行。 为啥这么做是可行的? 可能我比较笨,想了半天才想到。 因为每一列都是增序的,举个例子,假设matrix[0][5] >...
LeetCode 240. Search a 2D Matrix II 题目 O(m+n) class Solution { public: int n,m; bool searchMatrix(vector<vector<int>>& matrix, int target) { n = matrix.size(); if(n==0) return false; m = matrix[0].size();...
* 题目: 240.Search a 2D Matrix II * 网址:https://leetcode.com/problems/search-a-2d-matrix-ii/ * 结果:AC * 来源:LeetCode * 博客: ---*/#include<iostream>#include<vector>#include<stack>usingnamespacestd;classSolution{public:boolsearchMatrix(vector<vector<int>>& matrix,inttarget){if(mat...
func searchMatrix(matrix [][]int, target int) bool { // 矩阵行数 m := len(matrix) // 矩阵列数 n := len(matrix[0]) // 二分区间左边界初始化为 0 l := 0 // 二分区间右边界初始化为 m * n - 1 r := m * n - 1 // 当二分区间至少还存在 2 个数时,继续二分 for l < ...
/* * @lc app=leetcode id=240 lang=javascript * * [240] Search a 2D Matrix II * * https://leetcode.com/problems/search-a-2d-matrix-ii/description/ * * *//** * @param {number[][]} matrix * @param {number} target * @return {boolean} */var searchMatrix = function (matrix, ...
题目: Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 Integers in each row are sorted from left to right. The first integer of each row is greater than the last integer...