publicstaticintscoreOfString(String s){int num=0;for(int i=1;i<s.length();i++){num+=Math.abs(s.charAt(i)-s.charAt(i-1));}returnnum;} Runtime:1 ms, faster than100.00%of Java online submissions for Score of a String. Memory Usage:42 MB, less than50.00%of Java online submissio...
Given a balanced parentheses string s, return the score of the string. The score of a balanced parentheses string is based on the following rule: "()" has score 1. AB has score A + B, where A and B are balanced parentheses strings. (A) has score 2 * A, where A is a balanced ...
Given a string s of zeros and ones, return the maximum score after splitting the string into two non-empty substrings (i.e. left substring and right substring). The score after splitting a string is the number of zeros in the left substring plus the number of ones in the right substring...
给你一个由若干 0 和 1 组成的字符串 s ,请你计算并返回将该字符串分割成两个 非空 子字符串(即 左 子字符串和 右 子字符串)所能获得的最大得分。 「分割字符串的得分」为 左 子字符串中 0 的数量加上 右 子字符串中 1 的数量。 示例1: 输入:s = "011101" 输出:5 解释: 将字符串 s 划分...
Can you solve this real interview question? Maximum Score After Splitting a String - Given a string s of zeros and ones, return the maximum score after splitting the string into two non-empty substrings (i.e. left substring and right substring). The sco
The score after splitting a string is the number of zeros in the left substring plus the number of ones in the right substring. Example 1: Input: s = "011101" Output: 5 Explanation: All possible ways of splitting s into two non-empty substrings are: ...
https://leetcode-cn.com/problems/maximum-score-after-splitting-a-string/ 给你一个由若干 0 和 1 组成的字符串 s ,请你计算并返回将该字符串分割成两个 非空 子字符串(即左 子字符串和 右 子字符串)所能获得的最大得分。 「分割字符串的得分」为左 子字符串中 0 的数量加上 右 子字符串中 1...
Leetcode 1274 Number of Ships in a Rectangle Leetcode 1376 Time Needed to Inform All Employees Leetcode 694 Number of Distinct Islands Leetcode 586 Score of Parentheses 基于排列组合的DFS: 其实与图类DFS方法一致,但是排列组合的特征更明显 Leetcode 17 Letter Combinations of a Phone Number Leetcode ...
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The score after splitting a string is the number of zeros in the left substring plus the number of ones in the right substring. Example 1: Input: s = "011101" Output: 5 Explanation: All possible ways of splitting s into two non-empty substrings are: left = "0" and right = "11101...