reverse(nums,0, nums.length -1); reverse(nums,0, k -1); reverse(nums, k, nums.length -1); }// reverse array from begin to endprivatevoidreverse(int[] a,intbegin,intend){for(inttemp; begin < end; begin++, end--) { temp = a[begin]; a[begin] = a[end]; a[end] = temp...
2. Rotate first part: 4,3,2,1,5,6 3. Rotate second part: 4,3,2,1,6,5 4. Rotate the whole array: 5,6,1,2,3,4 或者 (1) reverse the array; (2) reverse the first k elements; (3) reverse the last n-k elements. 这个方法与Leetcode Reverse Words in a String II达成一致。
在处理问题时,通过移动i和j来达到我们想要的效果。注意,如果用same direction pointers去处理array时,array里已经processed的数据的相对位置不会有变化。 2. Two pointers in the reverse direction: 在此类问题中,pointer的结构如下图所示: 注意,用此方法的话不会保留processed数据的相对位置。 Examples: same directi...
size(); reverse(nums, 0, nums.size() - 1); reverse(nums, 0, k - 1); reverse(nums, k, nums.size() - 1); } void reverse(vector<int>& nums, int start, int end){ int temp; while(start < end){ temp = nums[start]; nums[start] = nums[end]; nums[end] = temp; start++...
publicListNodereverseList(ListNode head){if(head==null||head.next==null){returnhead;}ListNode newHead=reverseList(head.next);head.next.next=head;head.next=null;returnnewHead;} 对于迭代法也是类似的,但需要额外考虑一下,究竟应该保存链表的哪些节点。这里我们要保存的是它的前一个和后一个。这是因为...
ToString().TrimStart('-').Reverse();//转换为int，成功则返回if(int.TryParse(reversed.ToArray()...
给定一个整数数组nums,将数组中的元素向右轮转k个位置,其中k是非负数。 示例1: 输入:nums = [1,2,3,4,5,6,7], k = 3输出:[5,6,7,1,2,3,4]解释:向右轮转 1 步:[7,1,2,3,4,5,6]向右轮转 2 步:[6,7,1,2,3,4,5]向右轮转 3 步:[5,6,7,1,2,3,4] ...
题目:Reverse String(反转字符串) Write a function that reverses a string. The input string is given as an array of characters char[]. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory. You may assume all the ...
3. public String reverseVowels(String s) { 4. int i = 0, j = s.length () - 1; 5. char [] result = new char [s.length ()]; 6. while (i = j) { 7. char ci = s.charAt (i); 8. char cj = s.charAt (j); 9. if (!vowels.contains(ci)) { 10. result [i++] =...
leetcode 151 - reverse-words-in-a-string: 先把string按照空格分成词语,然后把这些词语从后往前组合 滑动窗口的方法,通常适用与寻找子串或者子数组的情况,分别设置左右指针,适时的移动左右指针,保证滑动窗口中的元素满足某个条件 Examples: leetcode 209. Minimum Size Subarray Sum#49 ...