Given a linked list, reverse the nodes of a linked listkat a time and return its modified list. kis a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple ofkthen left-out nodes in the end should remain as it is....
Given a linked list, reverse the nodes of a linked listkat a time and return its modified list. kis a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple ofkthen left-out nodes, in the end, should remain as it i...
class ReverseKGroupsLinkedList { public ListNode reverseKGroup(ListNode head, int k) { if (head == null || k == 1) { return head; } ListNode dummy = new ListNode(0); dummy.next = head; ListNode start = dummy; ListNode end = head; int count = 0; whi...
AI代码解释 publicclassSolution{publicListNodereverseBetween(ListNode head,int m,int n){if(m==n||head==null||head.next==null){returnhead;}ListNode pre=newListNode(0);pre.next=head;ListNode Mpre=pre;ListNode NodeM=head;ListNode NodeN=head;int mNum=1;int nNum=1;while(mNum<m&&NodeM!=nu...
leetcode Reverse Nodes in k-Group /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode *reverseKGroup(ListNode *head, int k) {...
(参考视频讲解:Leetcode力扣|206反转链表|递归|reverse linked list_哔哩哔哩_bilibili) # 定义一个链表节点类 class ListNode: def __init__(self, val=0, next=None): # 初始化函数 self.val = val # 节点的值 self.next = next # 指向下一个节点的指针 # 将给出的数组转换为链表 def linkedlist(li...
You may not alter the values in the list's nodes, only nodes itself may be changed. 题解: 直接用容器: classSolution{ public: ListNode*reverseKGroup(ListNode*head,intk) { if(head==NULL||head->next==NULL||k<=1) { returnhead; ...
Can you solve this real interview question? Reverse Nodes in k-Group - Given the head of a linked list, reverse the nodes of the list k at a time, and return the modified list. k is a positive integer and is less than or equal to the length of the linke
1190.Reverse-Substrings-Between-Each-Pair-of-Parentheses (H-) 1209.Remove-All-Adjacent-Duplicates-in-String-II (M+) 1586.Binary-Search-Tree-Iterator-II (H) 2197.Replace-Non-Coprime-Numbers-in-Array (H-) 2296.Design-a-Text-Editor (M+) 2751.Robot-Collisions (M+) 2764.is-Array-a-Preor...
0024 Swap Nodes in Pairs Go 60.3% Medium 0025 Reverse Nodes in k-Group Go 53.4% Hard 0026 Remove Duplicates from Sorted Array Go 50.3% Easy 0027 Remove Element Go 52.0% Easy 0028 Find the Index of the First Occurrence in a String Go 37.4% Medium 0029 Divide Two Integers Go 17.4...