leetcode:Reverse Integer(一个整数反序输出) Question:Reverse digits of an integer. Example1:x = 123, return 321Example2:x = -123, return -321 Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought through this! I...
reverseValue:Int): Int ={ if (x==0) reverseValue else { val remainder = ...
LeetCode | Reverse Integer Reverse Integer Total Accepted:72743Total Submissions:279370My Submissions QuestionSolution Reverse digits of an integer. Example1:x = 123, return 321 Example2:x = -123, return -321 click to show spoilers. Show Tags 思路:这一题就是将一个整型值逆序输出,转换成字符串...
leetcode——Reverse Integer 前言 leetcode的刷题记录,整理思路和一些理论细节。 Question 给出一个32比特大小的整数,对其逆序。 Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 Note: Assume we are dealing with an environment which could ...
Subscribeto see which companies asked this question. 2、代码实现 代码实现1、 通过不了LeetCode 代码解读 public static int reverse(int x) { if (x > Integer.MAX_VALUE || x < Integer.MIN_VALUE) { return 0; } boolean flag = false; //x是负数就是true,正数false ...
Question 7 Reverse Integer: Given a 32-bit signed integer, reverse digits of an integer. Example: 代码语言:javascript 复制 Input:123Output:321Input:-123Output:-321Input:120Output:21 Note: Assume we are dealing with an environment which could only store integers within the 32-bit signed integer...
int reverse(int x){ int tmp=0;//保留个位数 int sum=0;//存储反转过后的值 while(x) ...
LeetCode | Reverse Integer 逆序数据 Reverse Integer Total Accepted: 72743 Total Submissions: 279370My Submissions Question Solution Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321...
我用JS刷LeetCode | Day 2 | Reverse Integerwww.brandhuang.com/article/1583415034915 Question: Given a 32-bit signed integer, reverse digits of an integer. Note: Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231, 231...
classSolution:defreverse(self,x):""":type x: int:rtype: int"""x==0:return0str_x=str(x)x=''ifstr_x[0]=='-':x+='-'x)-1::-1].lstrip("0").rstrip("-")x=int(x)if-2**31<x<2**31-1:returnxreturn0