链接:https://leetcode-cn.com/problems/remove-linked-list-elements python # 移除链表元素,所有值相同的元素全部删掉 classListNode: def__init__(self, val): self.val = val self.next= None classSolution: # 删除头结点另做考虑 defremoveElements1(self,head:ListNode,val:int)->ListNode: # rm值相...
Can you solve this real interview question? Remove Linked List Elements - Given the head of a linked list and an integer val, remove all the nodes of the linked list that has Node.val == val, and return the new head. Example 1: [https://assets.leetc
## LeetCode 203classSolution:defremoveElements(self,head,val):""":type head: ListNode, head 参数其实是一个节点类 ListNode:type val: int,目标要删除的某个元素值:rtype: ListNode,最后返回的是一个节点类"""dummy_head=ListNode(-1)## 定义第一个节点是个 dummydummy_head.next=headcurrent_node=du...
classSolution {public: ListNode* removeElements(ListNode* head,intval) {if(!head)returnNULL; head->next = removeElements(head->next, val);returnhead->val == val ? head->next : head; } }; 类似题目: Remove Element Delete Node in a Linked List 参考资料: https://leetcode.com/problems/r...
class Solution { public: ListNode* removeElements(ListNode* head, int val) { if(head==NULL) return NULL; while(head!=NULL&&head->val==val) head=head->next; if(head==NULL) return NULL; ListNode* tem =head; while(tem->next){ if(tem->next->val==val){ tem->next=tem->next->next...
Remove all elements from a linked list of integers that have valueval. Example: Input: 1->2->6->3->4->5->6, val = 6 Output: 1->2->3->4->5 1. 2. 题解: 增加个头结点指向需要删除结点的前面就好了 classSolution{ public: ...
* Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ classSolution{ public: ListNode*removeElements(ListNode*head,intval) { if(head==NULL)returnhead; ...
简介:Remove all elements from a linked list of integers that have value val.Example Given: 1 –> 2 –> 6 –> 3 –> 4 –> 5 –> 6, val = 6 Return: 1 –> 2 –> 3 –> 4 –> Remove all elements from a linked list of integers that have value val. ...
# Definition for singly-linked list.# class ListNode:# def __init__(self, x):# self.val = x# self.next = Noneclass Solution: def removeElements(self, head: ListNode, val: int) -> ListNode: prev = ListNode(0) prev.next = head cur = prev while cur.next...
func removeElements(head *ListNode, val int) *ListNode { if head == nil { return head } var p1 ListNode p1.Next = head p2 := &p1 for head != nil { if head.Val == val { p2.Next, head = head.Next, head.Next } else { p2, head = head, head.Next } } return p1.Next ...