BA Interview Question Count and Say Deion: The count-and-say sequence is the sequence of integers with the first five terms as following: 1 is read off as “one 1” or 11. 11 is read off as “two 1s” or 21. 21 is read off as “one 2, then one 1” or 1211. Given an integ...
package leetcode.editor.cn;${question.content} public class $!velocityTool.camelCaseName(${question.titleSlug}){undefined public static void main(String[] args) {undefined Solution solution = new $!velocityTool.camelCaseName(${question.titleSlug})().new Solution();} ${question.code} } 就这...
Question 206. 反转链表 难度：简单 给你单链表的头节点 head ，请你反转链表，并返回反转后的链表。示例 1：输入：head = [1,2,3,4,5]输出：[5,4,3,2,1]示例 2：输入：head = [1,2]输出：[2,1]示例 3：输入：head = []输出：[]提示：链表中节点的数目范围是 [0, 5000] -5000 <= Node....
Solution2:翻转+对角线互换 class Solution { public: void rotate(vector<vector<int>>& matrix) { //原地算法1 for(int i = 0; i < matrix.size() >> 1; i++){ for(int j = 0; j < matrix.size(); j++){ swap(matrix[i][j],matrix[matrix.size()-i-1][j]); } } //对角线互换...
比如力扣第581. 最短无序连续子数组是一道很经典的数组类型题目，前后刷了三次，因为这是一道很经典的...
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Output:index1=1, index2=2 Question Tags: Array , Hash Table New Words: add up to:总计达 indices:index的复数 zero-based:从零开始的 Solution Ideas: 思路一: 两层遍历法:对于数组中的某一个数,对它及他以后的某个数求和,若和与target相等,则可确定这两值为所找的。此方式时间复杂度为O(nlogn)...
1. CodeTemplate就是自动生成的代码格式,不喜欢配置一的可以使用这种。 package leetcode.editor.cn; ${question.content} public class $!velocityTool.camelCaseName(${question.titleSlug}){ public static void main(String[] args) { Solution solution = new $!velocityTool.camelCaseName(${question.titleSl...
solution /** *@param{string[]}logs*@return{string[]} */varreorderLogFiles =function(logs) {conststrs = [];constnums = []; logs.map(log=>{constarr = log.split(' ');if(arr[1].match(/[0-9]/g)) { nums.push(log); }else{ ...