LeetCode All In One English | 简体中文 Provide all my solutions and explanations in Chinese for all the Leetcode coding problems. Same as this: LeetCode All in One 题目讲解汇总(持续更新中...) Click below image to watch YouTube Video Note: All explanations are written in Github Issues, ...
// 不要candidates[idx]，这时应该跳到下一个不相同的数，避免遇到和当前数相同数的情况 哪个
This repository contains the solutions and explanations to the algorithm problems on LeetCode. Only medium or above are included. All are written in C++/Python and implemented by myself. The problems attempted multiple times are labelled with hyperlinks.
1.2 5405. 形成两个异或相等数组的三元组数目(1442. Count Triplets That Can Form Two Arrays of Equal XOR) 中文版题目描述:https://leetcode-cn.com/problems/count-triplets-that-can-form-two-arrays-of-equal-xor/ 英文版题目描述:https://leetcode.com/problems/count-triplets-that-can-form-two-arra...
下面的思路借鉴自讨论区(https://leetcode.com/problems/maximum-xor-of-two-numbers-in-an-array/discuss/91049/Java-O(n%29-solution-using-bit-manipulation-and-HashMap)的一个解法。现在 Medium 的题目居然也需要看解答了,叹气。 代码语言:javascript 复制 class Solution { public int findMaximumXOR(int[...
if(Arrays.binarySearch(matrix[i], target) >= 0)//一维数组的二分法,输入数组和要搜索的值,返回索引号returntrue; }returnfalse; } 作者:ustcyyw 链接:https://leetcode-cn.com/problems/search-a-2d-matrix-ii/solution/240java-san-chong-fang-fa-xiang-jie-zui-you-jie-yo/来源:力扣(LeetCode) ...
=0) {// Find the first occurrence on the righthand side that can be swappedright--; }if(right>left) {// if we're already in the midpoint and the left pointer is odd then there is no swapres++;// handled this rightmost occurrence that was even => adjust to...
https://leetcode.com/contest/weekly-contest-368/problems/minimum-number-of-groups-to-create-a-valid-assignment/ Weekly Contest 371 2934.Minimum Operations to Maximize Last Elements in Arrays 题意分析: Weekly Contest 372 2939. Maximum Xor Product 题意分析: 题目解答: 第三题攻坚战: 1.见题知点...
上一题:LeetCode第3题:lengthOfLongestSubstring(C语言) 思路:利用归并排序的思想,将两个数组合并为一个有序的数组,求中位数即可。 doublefindMedianSortedArrays(int*nums1,intnums1Size,int*nums2,intnums2Size){inttotal_count=nums1Size+nums2Size;intsorted_nums[total_count];inti=0,j=0,k=0;while(...
You may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again). After you sell your stock, you cannot buy stock on next day. (ie, cooldown 1 day) Example: 代码语言:javascript 复制 prices = [1, 2, 3, 0, 2] maxProfit = 3 transac...