LeetCode All In One English | 简体中文 Provide all my solutions and explanations in Chinese for all the Leetcode coding problems. Same as this: LeetCode All in One 题目讲解汇总(持续更新中...) Click below image to watch YouTube Video Note: All explanations are written in Github Issues, ...
二分是吧，死也要用二分做。平时
LeetCode15. 三数之和 ☕ 题目:15. 三数之和 (https://leetcode-cn.com/problems/3sum/) ❓ 难度:简单 📕 描述: 给你一个包含 n 个整数的数组 nums,判断 nums 中是否存在三个元素 a,b,c ,使得 a + b + c = 0 ?请你找出所有和为 0 且不重复的三元组。 注意:答案中不可以包含重复的三...
Output: false Explanation: Each array should be divided in subarrays of size 3. Constraints: 1 <= nums.length <= 10^5 1 <= nums[i] <= 10^9 1 <= k <= nums.length Note: This question is the same as 846:https://leetcode.com/problems/hand-of-straights/ 划分数组为连续数字的集合。
This repository contains the solutions and explanations to the algorithm problems on LeetCode. Only medium or above are included. All are written in C++/Python and implemented by myself. The problems attempted multiple times are labelled with hyperlinks.
下面的思路借鉴自讨论区(https://leetcode.com/problems/maximum-xor-of-two-numbers-in-an-array/discuss/91049/Java-O(n%29-solution-using-bit-manipulation-and-HashMap)的一个解法。现在 Medium 的题目居然也需要看解答了,叹气。 代码语言:javascript 复制 class Solution { public int findMaximumXOR(int[...
LeetCode344 反转字符串https://leetcode-cn.com/problems/reverse-string/ 能直接访问头尾的就双指针 (3)链表 LeetCode25 Hard K个一组翻转链表https://leetcode-cn.com/problems/reverse-nodes-in-k-group/ 记得搞个fakeHead,防止头结点的翻转不好操作。
https://leetcode.com/contest/weekly-contest-368/problems/minimum-number-of-groups-to-create-a-valid-assignment/ Weekly Contest 371 2934.Minimum Operations to Maximize Last Elements in Arrays 题意分析: Weekly Contest 372 2939. Maximum Xor Product 题意分析: 题目解答: 第三题攻坚战: 1.见题知点...
// Solution 1: Problems as such, that put restrictions on data range and index range and focus on counting, can be solved with BIT. Use a hash table to map a discretized sequence to a consecutive one. 代码1 //Code 1 316 Remove Duplicate Letters ...
上一题:LeetCode第3题:lengthOfLongestSubstring(C语言) 思路:利用归并排序的思想,将两个数组合并为一个有序的数组,求中位数即可。 doublefindMedianSortedArrays(int*nums1,intnums1Size,int*nums2,intnums2Size){inttotal_count=nums1Size+nums2Size;intsorted_nums[total_count];inti=0,j=0,k=0;while(...