begin(), workers.begin()+finish); // 最强的finish 个 工人 for(int i = finish-1; i >= 0; --i) // 先找难的任务 { int t = tasks[i]; auto it = w.lower_bound(t); if(it != w.end()) w.erase(it);//能直接完成 else if(pills > 0) { a
中任选2个数字的方法个数再乘以 numCnt[...,但一定要注意的是,这样的中间两个 for 循环应该是从后往前遍历,不然会累加出错误的值,参见代码如下: 解法五: class Solution { public: int threeSumMulti.../issues/923 类似题目: 3Sum Smaller 3Sum Closest 3Sum 参考资料: https://leetcode.com/p...
力扣leetcode-cn.com/problems/next-permutation/ 题目描述 实现获取 下一个排列 的函数,算法需要将给定数字序列重新排列成字典序中下一个更大的排列。 如果不存在下一个更大的排列,则将数字重新排列成最小的排列(即升序排列)。 必须 原地 修改,只允许使用额外常数空间。 示例1: 输入:nums = [1,2,3] ...
二：137. 只出现一次的数字 IIleetcode-cn.com/problems/single-number-ii/?utm_campaign=lcsocial...
原题参考链接:https://leetcode-cn.com/problems/7LpjUW 分析: 简而言之,本题默认给出的是包含一个单独闭环的图,只需要按照输入edges的逆序定位到首次出现在闭环上的边,即可将图还原为树。 示例1: 1输入: edges = [[1,2],[1,3],[2,3]]2输出: [2,3] ...
火柴拼正方形(相等子集) https://leetcode.cn/problems/matchsticks-to-square/ 你将得到一个整数数组 matchsticks ,其中 matchsticks[i] 是第 i 个火柴棒的长度。你要用 所有的火柴棍 拼成一个正方形。你 不能折断 任何一根
{vector<int>arr={7,8,9,1,2,6,4,3};autocmpInc=[](inta,intb){returna<b;};autocmpDec=[](inta,intb){returna>b;};sort(arr.begin(),arr.end(),cmpInc);// sorts array in increasing ordersort(arr.begin(),arr.end(),cmpDec);// sorts array in decreasing orderfor(autoi:arr)...
Why are the ranges chosen while calling work() for x < i and x > i ? What is the use of merging blocks and what is the significance? class Solution { public: struct DSU { std::vector<int> f, siz; DSU(int n) : f(n), siz(n, 1) { std::iota(f.begin(), f.end(), 0)...
the problems have hints which will help you in building up ideas on how to solve them. These hints will be subtle enough to set you on a particular path for reaching the optimized solution, without giving away the answer too easily. After completing this Explore Card on Arrays, you will ...
My C++ Code for LeetCode OJ.Please give this repo a ⭐ if it inspires you. Thanks. 😊😩 Hate manually copy & pasting the example testcases when solving LeetCode problems? 👉 Try my LeetCode Testcase ExtractorNow I'm using a Chrome Extension I developed -- LeetCoder -- to ...