The array may contain multiple peaks, in that case return the index to any one of the peaks is fine. You may imagine thatnum[-1] = num[n] = -∞. For example, in array[1, 2, 3, 1], 3 is a peak element and your function should return the index number 2. Your solution should...
For example, in array[1, 2, 3, 1], 3 is a peak element and your function should return the index number 2. click to show spoilers. Credits: Special thanks to@tsfor adding this problem and creating all test cases. 分析:遍历数据,找波峰,即某一个大于相邻的点的点 public class Solution ...
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6 7 8 9 10 11 12 13 14 classSolution(object): defmissingNumber(self, nums): """ :type nums: List[int] :rtype: int """ if0notinnums: return0 m=max(nums) s=sum(nums) ms=(m+1)*m/2 ifms==s: returnm+1 return(m+1)*m/2-sum(nums)...
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problem 268. Missing Number solution1:等差数列求和公式 根据题意,(0, 1, 2,...,n),共有(n+1)个数,丢失了一个数之后,剩余的数组成的数组,求解丢失的数据。 等差数列求和减去数组累加和得到的结果即为所求数据。 class Solution { ...
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事情是这样的. 下面这个就是我在GitHub上面自动生成的LintCode表格. 当时先做的是LintCode, 大约有150来道。 现在转手来做LeetCode,作为复习和...
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