1、使用 DENSE_RANK() 进行排名会得到:1,1,2,3,4 2、使用 RANK() 进行排名会得到:1,1,3,4,5 3、使用 ROW_NUMBER() 进行排名会得到:1,2,3,4,5 最后再通过一个表格来说明下区别:下图是待排序的数据 通过3种函数排名之后的表格和区别: select name,price, row_number() (order by price desc) ...
row_number()over(partition by Company order by Salary) as rank_, count(1)over(partition by Company)/2 as even_mid, ceil(count(1)over(partition by Company)/2) as odd_mid from Employee )t where ( mod(cnt,2) = 0 and rank_ in (even_mid,even_mid + 1) ) or ( mod(cnt,2) = ...
1、使用 DENSE_RANK() 进行排名会得到:1,1,2,3,4 2、使用 RANK() 进行排名会得到:1,1,3,4,5 3、使用 ROW_NUMBER() 进行排名会得到:1,2,3,4,5 最后再通过一个表格来说明下区别:下图是待排序的数据 通过3种函数排名之后的表格和区别: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 select ...
SQL四大排名函数(ROW_NUMBER、RANK、DENSE_RANK、NTILE) 三、代码 AI检测代码解析 select Score,row_num `Rank` from( select Score,DENSE_RANK()over(order by Score desc) as row_num from Scores )a 1. 2. 3. 4. 5.
leetcode202 Happy Number 判断一个数是否为happy number。happy number是指,一个数,将其替换为其各位数字的平方和,重复这个过程,如果最终能得到1,这是happy number,如果这个过程陷入了一个不包含1的循环,则不是happy number 判断一个数是否为happy number。以19为例: 1^2 + 9^2 = 82 8^2 + 2^2 = ...
dense_rank函数 row_number函数 ntile函数 下面举个例子来展示一下这 4 种函数的作用: create table scores ( id number(6) ,score number(4,2) ); insert into scores values(1,3.50); insert into scores values(2,3.65); insert into scores values(3,4.00); ...
| score | rank | +---+---+ | 4.00 | 1 | | 4.00 | 1 | | 3.85 | 2 | | 3.65 | 3 | | 3.65 | 3 | | 3.50 | 4 | +---+---+ Accepted 483.3K Submissions 744.4K Acceptance Rate 64.9% FindBorderBarSize
https://leetcode.cn/problems/number-of-ways-to-reconstruct-a-tree 这道题曾经在周赛难度分top1呆了几年,如今已经不在难度分top5了。破局的关键是父节点的邻居数肯定不少于子节点,而根节点的邻居数一定是n-1。所以应该先找到根节点,然后逐层向下建树,子节点的邻居一定是父节点的子集,否则就是非法;如果子...
[LeetCode] Rank Scores 分数排行 Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" between ...
Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" between ranks. ...