1classSolution {2publicintmissingElement(int[] nums,intk) {3for(inti = 1; i < nums.length; i++) {4if(nums[i] - nums[i - 1] - 1 >=k) {5returnnums[i - 1] +k;6}7k -= nums[i] - nums[i - 1] - 1;8}9returnnums[nums.length - 1] +k;10}11} 再来是二分法。以后看...
If missing count < k, then must fall on the right side. l = mid + 1. Time Complexity: O(logn). n = nums.length. Space: O(1). AC Java: 1classSolution {2publicintmissingElement(int[] nums,intk) {3intn =nums.length;4if(nums[n - 1] - nums[0] - (n - 1 - 0) <k){...
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/missing-element-in-sorted-array 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 2. 解题 2.1 一次遍历 相邻的数做差,进行判断,对 k 进行更新,直到 k <= 0 停止 代码语言:javascript 代码运行次数:0 运行 AI代码解释 ...
LeetCode-Single Element in a Sorted Array Description: Given a sorted array consisting of only integers where every element appears twice except for one element which appears once. Find this single element that appears only once. Example 1: AI检测代码解析 Input: [1,1,2,3,3,4,4,8,8] Out...
Can you solve this real interview question? Single Element in a Sorted Array - You are given a sorted array consisting of only integers where every element appears exactly twice, except for one element which appears exactly once. Return the single eleme
1. Problem Descriptions:Given an array of integers nums sorted in non-decreasing order, find the starting and ending position of a given target value.If target is not found in the array, return [-1…
【leetcode】540. Single Element in a Sorted Array 题目如下: 解题思路:题目要求时间复杂度是O(logN),可以尝试使用二分查找法。首先数组是有序的,而且仅有一个元素出现一次,其余均为两次。我们可以先找到数组最中间的元素,记为mid。如果mid和mid-1以及mid+1都不相同,那么mid就是single number。如果mid和mid-...
- LeetCodeleetcode.com/problems/find-first-and-last-position-of-element-in-sorted-array/ 解题思路 1. 二分找元素,双指针找区间 class Solution { public: vector<int> searchRange(vector<int>& nums, int target) { vector<int> res(2, -1); int pos = bsearch(nums, target, 0, nums.size...
Runtime:1 ms, faster than54.31%of Java online submissions for Element Appearing More Than 25% In Sorted Array. Memory Usage:44.8 MB, less than5.97%of Java online submissions for Element Appearing More Than 25% In Sorted Array.
智能模式 1 行1,列 1 运行和提交代码需要登录 Case 1Case 2Case 3 nums = [4,7,9,10] k = 1 1 2 3 4 5 6 [4,7,9,10] 1 [4,7,9,10] 3 [1,2,4] 3 Source 该题目是 Plus 会员专享题 感谢使用力扣!您需要升级为 Plus 会员来解锁该题目升级Plus 会员...