核心代码如下: stringmergeAlternately(stringword1,stringword2){ // cout << word1.size() << endl; intlen1 = word1.size(); intlen2 = word2.size(); inti =0, j =0; stringres; res.reserve(len1 + len2); while(i < len1 || j < len2) { if(i < len1) { res.push_back(wo...
题目地址:https://leetcode-cn.com/problems/merge-strings-alternately/ 题目描述 给你两个字符串word1和word2。请你从word1开始,通过交替添加字母来合并字符串。如果一个字符串比另一个字符串长,就将多出来的字母追加到合并后字符串的末尾。 返回 合并后的字符串 。 示例1: 输入:word1 ="abc", word2 ="...
Can you solve this real interview question? Merge Strings Alternately - You are given two strings word1 and word2. Merge the strings by adding letters in alternating order, starting with word1. If a string is longer than the other, append the additional
题目地址:https://leetcode-cn.com/problems/merge-strings-alternately/ 题目描述 给你两个字符串 word1 和 word2 。请你从 word1 开始,通过交替添加字母来合并字符串。如果一个字符串比另一个字符串长,就将多出来的字母追加到合并后字符串的末尾。 返回...
祖传的手艺不想丢了,所以按顺序写一个leetcode的题解。计划每日两题,争取不卡题吧。 1768.交替合并字符串 力扣leetcode-cn.com/problems/merge-strings-alternately/ 比较基础的题目,使用两个指针分别从两个字符串的头部开始向后扫,按照先1后2的顺序进行合并。当某一个指针当前字符串末尾时则停止,然后将合并...
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/merge-strings-alternately 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 2. 解题 双指针模拟 代码语言:javascript 代码运行次数:0 运行 AI代码解释 class Solution { public: string mergeAlternately(string word1, string wo...
C++ 智能模式 1 2 3 4 5 6 class Solution { public: string mergeAlternately(string word1, string word2) { } }; 已存储 行1,列 1 运行和提交代码需要登录 Case 1Case 2Case 3 word1 = "abc" word2 = "pqr" 1 2 3 4 5 6 "abc" "pqr" "ab" "pqrs" "abcd" "pq" Source ...
word1和word2由小写英文字母组成 Runtime:1 ms, faster than85.58%of Java online submissions for Merge Strings Alternately. Memory Usage:41.5 MB, less than68.46%of Java online submissions for Merge Strings Alternately. --- 直接模拟即可。
word1: a b c d word2: p q 合并后: a p b q c d ``` 提示: + `1 <= word1.length, word2.length <= 100` + `word1` 和 `word2` 由小写英文字母组成 ### 地址 https://leetcode-cn.com/problems/merge-strings-alternately ### 题意 > 简单问题,直接暴力或者前缀和什么的 ### ...
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