我的解法:(与Spiral Matrix解法相同, 区别是rows和cols都是n, 定义count计数四边已经铺了数字的边框,定义num++;对四边分别for循环赋值, 内部与最外圈的区别就是多了一个count,包括起始条件+/-count, 终止条件+/-count; 前两个for顺序遍历, 中间插入判断条件break, 后两个for倒序;) (1.int[][],num,count;...
Given array nums = [-1, 0, 1, 2, -1, -4], A solution set is: [ [-1, 0, 1], [-1, -1, 2] ] 这个题目如果直接brute force的话,就是O(n^3), 三个for loop。 我们可以用一个for loop 去得到每个num,然后另外用O(n) 时间复杂度的[LeetCode] 1. Two Sum_Easy tag: Hash Table...
LeetCode Top 100 Liked Questions 34. Find First and Last Position of Element in Sorted Array(Java版; Medium) 题目描述 Given an array of integers nums sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the...
(The output array does not count as extra space for the purpose of space complexity analysis.) 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 第一次做; 核心:这道题主要是得有这么个意识: 不一定一次性求出结果; 可以先都求一部分, 然后再都求另一部分; temp的作用: 记录台阶; 两个做法...
Squaring a Sorted Array (easy) Triplet Sum to Zero (medium) Triplet Sum Close to Target (medium) Triplets with Smaller Sum (medium) Subarrays with Product Less than a Target (medium) Dutch National Flag Problem (medium) 3. Pattern: Fast & Slow pointers,快慢指针类型 ...
Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. 在一个升序的数组中,找出等于给定目标值首次出现后最后一次出现的位置,复杂度为O(log n),若果没有等于目标值的就返回[-1,-1] ...
我虽然是用python的，但是看到各位道友直接调用API，然后说什么x行搞定，我觉得不要误人子弟好嘛。如果题目排序不是重点，你可以直接用sort或则sorted。这题明显是考双指针操作字符数组，你们直接调用reverse、split、replace或[::-1]是不是在秀下限？
题方法2)按topic刷,但是从string/array这些做起(毕竟就这些看着熟悉)。结果发现的很多题需要用到dp,搜索,树等等,全要现学。每道题方法不一样,除了码字速度变快一点长进都没有。 (错误的题方法3)一个人的战斗。转专业是的旅程,很容易极不自信或自信过头。结合刷题1和2,当我面对一道medium题两个小时...
64Minimum Path Sum](https://leetcode.com/problems/minimum-path-sum/)MediumSolution.java 70Climbing StairsEasySolution.java 72Edit DistanceMediumSolution.java 73Set Matrix ZeroesMediumSolution.java 77CombinationsMediumSolution.java 88Merge Sorted ArrayEasySolution.java ...
Given an array of strings, group anagrams together. For example, given:["eat", "tea", "tan", "ate", "nat", "bat"], Return: [ ["ate","eat","tea"], ["nat","tan"], ["bat"] ] Note: For the return value, eachinnerlist's elements must follow the lexicographic order. ...