然后用result的存储最大的count,并和最后的count对比,返回最大的count## 精简版本classSolution:deffindMaxConsecutiveOnes(self,nums:List[int])->int:max_count=count=0fornuminnums:ifnum==1:count+=1max_count=max(max_count,count)else:count=0# 无视0即可returnmax_count...
Leetcode之Max Consecutive Ones 问题 . The maximum number of consecutive 1s is 3. Note: 1.The input array will only contain 0 and 1. 2.The...问题描述: Given a binary array, find the maximum number of consecutive 1s in this array. 示例: Input 第九周_Leetcode 题目一: 485. Max Co...
public int findMaxConsecutiveOnes(int[] nums) { if (nums == null || nums.length == 0) { return 0; } int maxLen = 0; int subLen = 0; for (int i = 0; i < nums.length; i++) { while (i < nums.length && nums[i] == 1) { subLen++; i++; } if (subLen > maxLen...
class Solution { public int findMaxConsecutiveOnes(int[] nums) { if(nums == null || nums.length < 1) return 0; int count = 0, temp = 0; for(int i=0; i 跟我的代码不同之处在于我是当当前遍历的元素时1是比较max与temp的大小然后取较大的一个,它是当当前遍历的元素是0的时候才进行判...
这个循环一遍记录最大连续值即可,C++实现如下: intfindMaxConsecutiveOnes(vector<int>&nums) {intcount=0;intmax=0;for(inti=0;i<nums.size();i++) {if(nums[i]==1) { count++; }else{ count=0; }if(count>max) max=count; }returnmax; }...
classSolution {public:intfindMaxConsecutiveOnes(vector<int>&nums) {intres =0, sum =0;for(intnum : nums) { sum= (sum + num) *num; res=max(res, sum); }returnres; } }; Github 同步地址: https://github.com/grandyang/leetcode/issues/485 ...
Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3. 1. 2. 3. 4. 5. Note: The input array will only contain 0 and 1. The length of input array is a positive integer and will not exceed 10,000 ...
485. Max Consecutive Ones solution1: AI检测代码解析 class Solution { public: int findMaxConsecutiveOnes(vector<int>& nums) { if(nums.empty()) return 0; int ans = 0, max = INT_MIN; for(int i=0; i<nums.size(); i++) ...
// #485 Description: Max Consecutive Ones | LeetCode OJ 解法1:水题。 // Solution 1: Trivial. 代码1 // Code 1 486 Predict the Winner // #486 预测赢家 描述:给定一个数组,每个元素表示一个分数。俩人轮流,每次从左端或右端拿走一个分数,如此直到拿完。分高的人赢。问先手是否必胜? // #486 ...
C++ 智能模式 1 2 3 4 5 6 class Solution { public: int findMaxConsecutiveOnes(vector<int>& nums) { } }; 已存储 行1,列 1 运行和提交代码需要登录 Case 1Case 2 nums = [1,1,0,1,1,1] 1 2 [1,1,0,1,1,1] [1,0,1,1,0,1] Source ...