1572. Matrix Diagonal SumEasy Topics Companies Hint Given a square matrix mat, return the sum of the matrix diagonals. Only include the sum of all the elements on the primary diagonal and all the elements on the
【leetcode】1572. Matrix Diagonal Sum 题目如下: Given a square matrixmat, return the sum of the matrix diagonals. Only include the sum of all the elements on the primary diagonal and all the elements on the secondary diagonal that are not part of the primary diagonal. Example 1: Input: m...
1572. Matrix Diagonal Sum解题方法遍历数组每次累加mat[i][j]和mat[i][len(mat)-1-j],如果j == len(mat) - 1 - j的话就去掉一个mat[i][j],最后返回Sum。 时间复杂度:O(mn) 空间复杂度:O(1)代码class Solution: def diagonalSum(self, mat: List[List[int]]) -> int: Sum = 0 i = j...
点乘的计算是sum(xi*yi)。既然稀疏,那我们就只保存(i,val)非0值的记录。然后按照哈希表的方式,求交集。相乘求和即可。 1572 Matrix Diagonal Sum 题意:给定方阵,请求出正反对角线元素之和。 难度:easy 解法:水题。 1574 Shortest Subarray to be Removed to Make Array Sorted 题意:给定数组arr,你可以从中...
https://leetcode.com/problems/diagonal-traverse-ii/ sdn com version 搜索 LeetCode 第 186 场周赛(1060/3107,前34.1%) 编程算法 全国排名:1060 / 3107,34.1%;全球排名:4145 / 11687,35.5% Michael阿明 2020/07/13 3730 LeetCode笔记:Biweekly Contest 33 比赛记录 ...
3242 Design Neighbor Sum Service 题意:给定n x n矩阵,包含了0~n^2-1的不同值。请实现函数adjacentSum(val),求出val值所在位置的上下左右四边的求和;函数diagonalSum(val),求出val值所在位置的相邻四个角的求和。 难度:easy 解法:对值->位置做出映射,先找到位置,然后求和即可。
C++ 智能模式 1 2 3 4 5 6 class Solution { public: int diagonalSum(vector<vector<int>>& mat) { } }; 已存储 行1,列 1 运行和提交代码需要登录 Case 1Case 2Case 3 mat = [[1,2,3],[4,5,6],[7,8,9]] 1 2 3 [[1,2,3],[4,5,6],[7,8,9]] [[1,1,1,1],[1,1,...
nt diagonalSum(int** mat, int matSize, int* matColSize){int ans = 0;for(int i = 0;i < matSize;i++)ans += mat[i][i] + mat[i][matSize - 1 - i];if(matSize & 1) ans -= mat[matSize/2][matSize/2];return ans;} ...
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