To make the string good, you can choose two adjacent characters that make the string bad and remove them. You can keep doing this until the string becomes good. Returnthe stringafter making it good. The answer is guaranteed to be unique under the given constraints. Notice that an empty str...
Can you solve this real interview question? Make The String Great - Given a string s of lower and upper case English letters. A good string is a string which doesn't have two adjacent characters s[i] and s[i + 1] where: * 0 <= i <= s.length - 2 * s[i
1544. Make The String Great solution#1:Brute-Force; code 注意1,如何判断两个字符是同一个字母的大小写呢?! 注意2,for循环的限制条件; 注意3,while循环的条件,或者外层循环结束的条件; solution#2: two pointers. code solution#3: string特性; code 也可以使用队列; 参考 1.leetcode_easy_string_1544. ...
1. leetcode_easy_string_1544. Make The String Great; 完
A set of practice note, solution, complexity analysis and test bench to leetcode problem set - leetcode/No_1544_Make The String Great at b58bcceb0ea27d0756ad72fb6a64b3b547fae221 · brianchiang-tw/leetcode
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1544 Make The String Great 题意:给定字符串s,如果相邻字符存在同字母大小写的情况,比如“aAEe”这种,则都删除。持续删除这种对子,直到不存在为止。返回结果。 难度:easy 解法:凡是这种类似祖玛一样的删除+靠拢逻辑,都可以用栈处理。 1545 Find Kth Bit in Nth Binary String ...
com/problems/make-the-string-great 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 题解 代码语言:javascript 代码运行次数:0 运行 AI代码解释 class Solution { int delta = 'a' - 'A'; public String makeGood(String s) { StringBuilder builder = new StringBuilder(s); int len...
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这道题也会用的到栈,但是如果存储字符...LeetCode 32. Longest Valid Parentheses Given a string containing just the characters '(' and ')', find the length of the longest valid (well-formed) parentheses substring. Example 1: Example 2: 解法一:用栈stack 解法二:动态规划DP ...猜你喜欢...