Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.According to the definition of LCA on Wikipedia:“The lowest common ancestor is defined between two nodes p and q as the lowest node in T that has both p and q as descendants (wher...
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST. According to thedefinition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (wh...
Leetcode|BST属性|530. BST最小绝对差(BST中序遍历=升序数组) 【BST的重要属性之一】:BST中序遍历 = 升序数组 遇到在BST上求最值,差值等,都要思考一下二叉搜索树可是有序的,要利用好这一特点。 代码语言:javascript 代码运行次数:0 /** * Definition for a binary tree node. * struct TreeNode { * i...
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST. According to thedefinition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (wh...
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST. According to thedefinition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodespandqas the lowest node inTthat has bothpandqas descendants (where we allow a ...
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST. According to thedefinition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (wh...
给定一棵二叉树的根节点 root,返回给定节点 p 和 q 的最近公共祖先(LCA)节点。 如果 p 或 q 之一不存在于该二叉树中,返回 null。 树中的每个节点值都是互不相同的。 根据维基百科中对最近公共祖先节点的定义:“两个节点 p 和 q 在二叉树 T 中的最近公共祖先节点是后代节点中既包括 p 又包括 q 的最...
与Contains Duplicate II 类似概念. TreeSet有BST 因此可以直接用, 而不用自己构建BST 简化题目里面的重要条件 Math.abs(A-B) <= t 而推断出需要用 TreeSet.ceiling(x): return number greater or equal to x. 这个用法要记住吧, 没别的捷径.
二叉树的最近公共祖先本题比235稍微难一些,235题可以通过数值的大小判断左右子树,该题不是BST不行。 // 递归:对每个节点对应的子树,若该子树不含有p或q,返回nullptr; // 否则,如果p和q分别位于当前子树根节点两侧,则返回当前节点, // 否则(p和q在同一侧,或者只有某一侧有p或q)返回来自左边或右边的LCA。
1902.Depth-of-BST-Given-Insertion-Order (H-) LCA 1123.Lowest-Common-Ancestor-of-Deepest-Leaves (M+) (aka. LC.865) 235.Lowest-Common-Ancestor-of-a-Binary-Search-Tree (M) 236.Lowest-Common-Ancestor-of-a-Binary-Tree (M+) 1644.Lowest-Common-Ancestor-of-a-Binary-Tree-II (M+) 1676.Lo...