1.题目描述 Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Your goal is to reach the last index in the minimum number of jumps. For example: Given array ...
Can you solve this real interview question? Jump Game II - You are given a 0-indexed array of integers nums of length n. You are initially positioned at nums[0]. Each element nums[i] represents the maximum length of a forward jump from index i. In other
【LeetCode】Jump Game II Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Your goal is to reach the last index in the minimum number of jumps. For example...
LeetCode 45. Jump Game II 程序员木子 香港浸会大学 数据分析与人工智能硕士在读 来自专栏 · LeetCode Description Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that ...
原题 题目:45. Jump Game ⅡGiven an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at tha…
45. 跳跃游戏 II leetcode 每个元素 nums[i] 表示从索引 i 向前跳转的最大长度。换句话说,如果你在 nums[i] 处,你可以跳转到任意 nums[i + j] 处: Michel_Rolle 2024/02/11 2.7K0 贪心——45. 跳跃游戏 II 编程算法 来源:力扣(LeetCode) 链接:https://leetcode.cn/problems/jump-game-ii 向着百...
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45. 跳跃游戏 II - 给定一个长度为 n 的 0 索引整数数组 nums。初始位置为 nums[0]。 每个元素 nums[i] 表示从索引 i 向后跳转的最大长度。换句话说,如果你在 nums[i] 处,你可以跳转到任意 nums[i + j] 处: * 0 <= j <= nums[i] * i + j < n 返回到达 nums[n - 1]
【LeetCode】45. Jump Game II Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Your goal is to reach the last index in the minimum number of jumps. ...
来源：力扣（LeetCode）链接：https://leetcode-cn.com/problems/jump-game-ii/著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。解法一：穷举法 首先，如果nums的长度为1，因为不需要走，直接返回0；如果nums的长度为2，由于一定可以到达最后一个位置，而且至少需要一步，直接返回1；当不是前...