import java.util.Arrays; public class Main { public static void main(String[] args) { int[] nums1 = {1, 2, 3, 4, 5, 6, 7}; int k1 = 3; rotate(nums1, k1); System.out.println("轮转后的数组:" + Arrays.toString(nums1)); // 输出:[5, 6, 7, 1, 2, 3, 4] int[] n...
There are two sorted arrays A and B of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log(m + n)). 分析 这是一道非常经典的题。这题更通用的形式是,给定两个已经排序好的数组,找到两者所有元 素中第 k 大的元素。 O(m ...
思路一Code:2080测试用例—107ms(beats 6.25%)时间复杂度:O(N*logN)………假设Collections.sort()为快速排序O(N*logN) 1publicdoublefindMedianSortedArrays(int[] nums1,int[] nums2) {2List<Integer> list =newArrayList<Integer>();3for(inti = 0; i < nums1.length; i++) {4list.add(nums1[i]...
import java.util.Arrays; class Solution { public int longestConsecutive(int[] nums) { if(nums==null || nums.length==0) return 0; Arrays.sort(nums); //因为input check后数组中至少有一个元素, 所以将maxLen和currLen初始化为1 int maxLen = 1, currLen = 1; //当前元素和前一个元素比较 f...
1.4 Median of Two Sorted Arrays 1.5 Longest Consecutive Sequence 1.6 Two Sum 1.7 Valid ...
350HashTable;TwoPointers;BinarySearch;Intersection of Two Arrays II 380Array;HashTable;Desgin;Insert Delete GetRandom O(1) 381Array;HashTable;Desgin;Insert Delete GetRandom O(1) - Duplicates allowed 389HashTable;Find the Difference 409HashTable;Longest Palindrome ...
Demonstrate all the questions on LeetCode in the form of animation.(用动画的形式呈现解LeetCode题目的思路) - MisterBooo/LeetCodeAnimation
如下是宫水三叶大神的Java解,使用了PriorityQueue classSolution{publicintscheduleCourse(int[][]courses){Arrays.sort(courses,(a,b)->a[1]-b[1]);PriorityQueue<Integer>q=newPriorityQueue<>((a,b)->b-a);intsum=0;for(int[]c:courses){intd=c[0],e=c[1];sum+=d;q.add(d);if(sum>e)sum...
他人的整理与总结: https://leetcode.wang/ 1. & 15. K-sum 问题 此类问题的解决方法: 第一种方法:暴力法,遍历 K 轮,求几个数字的和就...
class Solution { public boolean canAttendMeetings(Interval[] intervals) { Arrays.sort(intervals, new Comparator<Interval>() { @Override public int compare(Interval l, Interval r) { return l.start - r.start; } }); Integer lastEnd = null; for (Interval it : intervals) { if (lastEnd==...