}classSolution {public://just reuse the solution of "Merge Intervals", quite straight forwardvector<Interval> insert(vector<Interval> &intervals, Interval newInterval) { intervals.push_back(newInterval);returnm
[LeetCode] 57. Insert Interval You are given an array of non-overlapping intervalsintervalswhereintervals[i] = [starti, endi]represent the start and the end of theithinterval andintervalsis sorted in ascending order bystarti. You are also given an intervalnewInterval = [start, end]that repr...
Question Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Given intervals [1,3],[6,9], insert and merge ...
public List<Interval> insert(List<Interval> intervals, Interval newInterval) { intervals.add(newInterval); return merge(intervals); } class LinkedNode { Interval val; LinkedNode next; public LinkedNode(Interval val, LinkedNode next) { this.val = val; this.next = next; } } public List<Inte...
一个简单的思路是将 intervals 和 newInterval 合并成一个数组并排序，那么问题就和 56. 合并区间 类似，而 56. 合并区间 是一个中等题，思路参考 56. 合并区间 即可。代码 语言支持: Python3 class Solution: def insert(self, intervals: List[List[int]], newInterval: List[int]) -> List[List[int...
力扣leetcode-cn.com/problems/insert-interval/ 题目描述 给出一个无重叠的,按照区间起始端点排序的区间列表。 在列表中插入一个新的区间,你需要确保列表中的区间仍然有序且不重叠(如果有必要的话,可以合并区间)。 示例1: 输入:intervals = [[1,3],[6,9]], newInterval = [2,5] 输出:[[1,5],[...
https://leetcode-cn.com/problems/insert-interval/ 思路 这道题目合并的情况有很多种,想想都让人头疼。 我把这道题目化为三步: 步骤一:找到需要合并的区间 找到插入区间需要插入或者合并的位置。 代码如下: int index = 0; // intervals的索引
来源：力扣（LeetCode）链接：https://leetcode-cn.com/problems/insert-interval/著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。解法一：遍历数组 首先如果intervals为空，因为不需要处理合并，所以直接返回一个区间newInterval；如果intervals不为空，声明1个变量length记录intervals的区间数，然后...
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