Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST. Note that there may exist multipl...
left(NULL), right(NULL) {}* };*/class Solution {public:TreeNode* insertIntoBST(TreeNode* root, int val) {if(root==NULL){//递归边界root=new TreeNode(val);return root;}if(val==root->val){//查找成功,说明结点已经存在,直接返回
Description: Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST. Note that there may ...
left=insertIntoBST(root.left, val); return root; } } 解法二 迭代 class Solution { public TreeNode insertIntoBST(TreeNode root, int val) { if(root==null) return new TreeNode(val); TreeNode curr=root; while(true){ if(curr.val<val){ if(curr.right==null){ curr.right=new TreeNode...
开始修改二叉搜索树 ❞701.二叉搜索树中的插入操作链接: https://leetcode-cn.com/problems/insert-into-a-binary-search-tree/给定二叉搜索树(BST)的根节点和要插入树中的值,将值插入二叉搜索树。返回插入后…
TreeNode*insertIntoBST(TreeNode*root,intval) { if(root==NULL) { root=newTreeNode(val); } traversal(root,val); returnroot; } 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. ...
701. 二叉搜索树中的插入操作谢谢你，伪装成中等题的简单题桑 秒
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