target) {7//corner case8if(nums ===null|| nums.length === 0)return-1;910//normal case11let start = 0;12let end = nums.length - 1;13while(start + 1 <end) {14let mid = Math.floor(start + (end - start) / 2);15if(nums[mid] ===target) {16return...
1/**2* @param {number[]} nums3* @return {number}4*/5varsingleNonDuplicate =function(nums) {6let start = 0;7let end = nums.length / 2;8while(start <end) {9let mid = Math.floor((start + end) / 2);10if(nums[mid * 2] != nums[mid * 2 + 1]) {11end =mid;12}else{...
力扣leetcode-cn.com/problems/search-in-rotated-sorted-array-ii/ 题目描述 已知存在一个按非降序排列的整数数组 nums ,数组中的值不必互不相同。 在传递给函数之前,nums 在预先未知的某个下标 k(0 <= k < nums.length)上进行了 旋转 ,使数组变为 [nums[k], nums[k+1], ..., nums[n-1],...
target) {7//corner case8if(nums ===null|| nums.length === 0)return-1;910//normal case11let start = 0;12let end = nums.length - 1;13while(start + 1 <end) {14let mid = Math.floor(start + (end - start) / 2);15if(nums[mid] ===target) {16return...
[0]); const ans = new Array(n).fill(0); for (let i = 0; i < n; i++) { let left = 0; let right = n - 1; let target = -1; while (left <= right) { const mid = Math.floor((left + right) / 2); if (startIntervals[mid][0] >= intervals[i][1]) { ...
You may assume all elements in the array are non-negative integers and fit in the 32-bit signed integer range. 桶排序 复杂度 O(N) 时间 O(N) 空间 思路 假设有N个元素A到B。 那么最大差值一定大于floor[(B - A) / (N - 1)],floor就是向下取整 ...
int ifloor=floor(x),iceil=ceil(x); if(x-ifloor<e||iceil-x<e){ return true; } return false; } 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 题目3 ID面试题11 把一个数组最开始的若干个元素搬到数组的末尾,我们称之为数组的旋转。输入一个递增排序的数组的一个旋转,输出旋转数组的...
The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the Bit Manipulation(easy)三道题 , find the majority element. The majority element is the element that appears mo...
原题地址:https://leetcode-cn.com/problems/search-in-rotated-sorted-array-ii/ 题目描述: 假设按照升序排序的数组在预先未知的某个点上进行了旋转。 ( 例如,数组 [0,0,1,2,2,5,6] 可能变为 [2,5,6,0,0,1,2] )。 编写一个函数来判断给定的目标值是否存在于数组中。若存在返回 true,否则返回...
You are given a 0-indexed binary string array bank representing the floor plan of the bank, which is an m x n 2D matrix. bank[i] represents the ith row, consisting of '0's and '1's. '0' means the cell is empty, while'1' means the cell has a security device. There is one ...