Stringtisgenerated by random shufflingstringsand then add one more letter at a random position. Find the letter that was addedint. 字符串s和t由小写字母组成,其中t是通过将s中的字母顺序打乱并在一个随机位置插入某个字母生成的,在找出t中插入的字母。 解: 1、这个字母可能是s中已有的或者是新的字母但...
Can you solve this real interview question? Find the Difference - You are given two strings s and t. String t is generated by random shuffling string s and then add one more letter at a random position. Return the letter that was added to t. Exampl
Find the Difference 问题描述 Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was a...
impl Solution { pub fn find_the_difference(s: String, t: String) -> char { s // 转成字节切片 .as_bytes() // 转成迭代器 .iter() // 串上 t 的字节迭代器 .chain(t.as_bytes().iter()) // 使用 fold 积累 ans ,初始为 0 , // 对每个字符都执行异或操作, // 这样最后的值就是...
Find the letter that was added int. Example: Input: s = "abcd" t = "abcde" Output: e Explanation: 'e' is the letter that was added. 要完成的函数: char findTheDifference(string s, string t) 说明: 1、把字符串s随机打乱,然后在任意位置添加一个字母,构成字符串t。要找出这个添加的字母。
Find the letter that was added in t. Example: Input: s = "abcd" t = "abcde" Output:e Explanation: 'e' is the letter that was added. 将字符串s洗牌,在插入一个字符,得到字符串t,求这个插入的字符。 class Solution { public: char findTheDifference(string s, string t) { vector<int> co...
不过这里要先将字符“a”转换为 ASCII,才能进行异或运算。 解题代码: ## LeetCode 389E Find the differencefromtypingimportListclassSolution:deffindTheDifference(self,s:str,t:str)->str:c=0## 用 0 和 s 中的每个字母进行异或运算forlins:c=c^ord(l)## ord 转换为 ASCIIprint(c)## 打印中间临时...
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4. 5. 6. 7. 8. 9. please: Input: s = "a" t = "aa" Output: a 2、代码实现 AI检测代码解析 public class Solution { public static char findTheDifference(String s, String t) { if (s == null || t.length() == 0) return t.charAt(0); ...
文件列表 FindDifference-master.zip (预估有个2文件) FindDifference-master findTheDifference.java 2KB ReadME.md 428B 立即获取 点赞 收藏 分享 用户评论 暂无评论 提交评论 推荐下载leetcode卡 leetcoder:字母编码器 \"LeetCode卡片-字母编码器\"是一款专为编程爱好者设计的工具,它基于LeetCode平台,...